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AnnZ [28]
3 years ago
9

How do forces relate to matter?

Chemistry
1 answer:
gavmur [86]3 years ago
4 0
There are 4 states of matter-
liquid, gas, solid, plasma
Understanding how forces interact with each one
we can use that as a system to classify new things.
very applicable in engineering
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The table shows the thickness, top density, and bottom
OleMash [197]

\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}

As depth increases, the density of the layers decreases.

  • Thanks.
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3 0
3 years ago
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Which atomic model proposed that electrons move in specific orbits the nucleus of an atom?​
MrRa [10]

Bohr's atomic model proposed that electrons move in specific orbits around the nucleus of an atom.

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3 years ago
What is the empirical formula of a compound that is 41.4% Strontium, 13.24%
Pepsi [2]

Answer:

Empirical Formula N2O6Sr Strontium Nitrate

Explanation:

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6 0
2 years ago
What is the molarity of formaldehyde in a solution containing 0.25 grams of formaldehyde per mL?
Vikentia [17]

Answer:

8.33mol/L

Explanation:

First, let us calculate the molar mass of of formaldehyde (CH2O). This is illustrated below:

Molar Mass of CH2O = 12 + (2x1) + 16 = 12 + 2 + 16 = 30g/mol

Mass of CH2O from the question = 0.25g

Number of mole CH2O =?

Number of mole = Mass /Molar Mass

Number of mole of CH2O = 0.25/30 = 8.33x10^-3mole

Now we can calculate the molarity of formaldehyde (CH2O) as follow:

Number of mole of CH2O = 8.33x10^-3mole

Volume = 1mL

Converting 1mL to L, we have:

1000mL = 1L

Therefore 1mL = 1/1000 = 1x10^-3L

Molarity =?

Molarity = mole /Volume

Molarity = 8.33x10^-3mole/1x10^-3L

Molarity = 8.33mol/L

Therefore, the molarity of formaldehyde (CH2O) is 8.33mol/L

3 0
3 years ago
What information is needed to calculate the percent composition of a compound
IrinaVladis [17]

Percent Composition by Mass. Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.

The best answer. :)

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3 years ago
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