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Arlecino [84]
3 years ago
10

What is20 grams of HNO^3

Chemistry
2 answers:
morpeh [17]3 years ago
7 0

63.01284*20=1260.568

Galina-37 [17]3 years ago
3 0

Explanation:

Here are the answers for both of the question you send :)

hope this helps you to understand:)

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(You do) If you have 47.2 mol of Na available, along with an excess of Cl₂, how many grams of NaCl can you produce?
IrinaVladis [17]

Answer:

2,760 grams NaCl

Explanation:

To find grams of NaCl, you need to (1) convert moles of Na to moles of NaCl (via mole-to-mole ratio from reaction) and (2) convert moles of NaCl to grams (via molar mass from periodic table). The final answer should have 3 significant figures based on the given measurement.

2 Na + Cl₂ --> 2 NaCl

Molar Mass (NaCl) = 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl) = 58.44 g/mol

47.2 moles Na           2 moles NaCl              58.44 grams

----------------------  x  ---------------------------  x  -------------------------  =
                                   2 moles Na                   1 mole NaCl

= 2,758.368 grams NaCl

= 2,760 grams NaCl

5 0
2 years ago
Describe some conditions in Antarctica that could lead to chemical weathering
harkovskaia [24]
There's a heck ton of snow! What does that mean? It means metals that may not be water-soluble can rust.  <span />
5 0
4 years ago
Solve and show work. Li2S + 2 HNO3 --&gt; 2 LiNO3 + H2S (a) Calculate the mass of lithium sulfide that will react with 250 mL of
Elenna [48]

Li2S + 2 HNO3 --> 2 LiNO3 + H2S

Li2 S  +   H2 N2 O2  -->   Li2 N2 O5   +   H2 S

Li S + H2 N2 O5 -> Li N2 O5 + H2 S

Li2 S2 + H4 N4 O10 -->  Li2 N4 O10 + H4 S2

Li^2  S^2  +  H^4 N^4 O^10  --> Li^2 N^4  O^10  +  H^4 S^2

7 0
3 years ago
Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
Misha Larkins [42]
Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

So, the required volume of HCl is 541,54 mL

Have a nice day!
8 0
3 years ago
Which of the following are examples of chemical changes? Select all that apply.
Travka [436]

A B and C are all chemical changes. paper tearing is not.

6 0
3 years ago
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