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Alisiya [41]
3 years ago
13

Relationship between voltage, resistance and current in a circuit

Physics
1 answer:
Lena [83]3 years ago
8 0

Answer:

V = I×R

where -

V = potential difference across

I = current flowing in the circuit

R = Equivalent Resistance in the circuit

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If an object accelerating at −1.5m/s^2 takes 1.2s to reach 5.0m/s, what was its initial speed?
USPshnik [31]

-1.5 m/s^2 x 1.2 seconds = -1.8 m/s

It is a negative value which means the object slowed down. The object would have originally been going that amount more.


5.0 + 1.8 = 6.8 m/s


answer: 6.8 m/s

3 0
2 years ago
The internal energy of a system....
Angelina_Jolie [31]

Answer:

C. Equals the sum of all forms of energy contained within the system.

D. Equals the heat entering the system at constant volume.

E. Equals the heat entering the system plus the work done on the system

Explanation:

Internal energy is defined as the sum of internal kinetic energy and internal potential energy, that is, the energy contained within the system.

The first law of thermodynamics relates the change in the internal energy with the heat entering the system (Q) and work done on the system (W), with the following expression:

\Delta U=Q+W

If the system is at constant volume the work done is zero. Therefore, the heat entering the system increases its internal energy:

\Delta U=Q

5 0
3 years ago
Name three forces involved in brushing your teeth.
Viefleur [7K]
Three forces involved in brushing your teeth are first push, then pull, then push.
3 0
3 years ago
A reactor operating at 1 MW is scrammed by instantaneous insertion of $5.00 of negative reactivity. Approximately how long does
Novosadov [1.4K]

Answer:

time is 3333.33 min or 55.55 hr

Explanation:

given data

reactor operating = 1 MW

negative reactivity =  $5

power = 1 miliwatt

to find out

how long does it take

solution

we know here power coefficient that is

power coefficient = \frac{10^{6} }{10^{6} }

power coefficient = 1

so time required to reach power is

power =  reactivity × time / power coefficient + reactor operating

1 × 10^{-3} = -5 t / 1  +  1 × 10^{6}

5t =  10^{6} - 10^{-3}

t = 199999.99 sec

so time is 3333.33 min or 55.55 hr

4 0
3 years ago
Can someone help me with 1-2
ira [324]
Can't really plot a graph here for question 1.

2a) The car speeds up from A to B. The car travels at a constant speed from B to C. The car slows down to a stop from C to D.

b) From the graph, at 10 seconds, the car is moving at 20 m/s.
4 0
3 years ago
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