C is the answer to the question
Answer:
r=6.05km/hr
z=59.1 degree to the horizontal
Explanation:
A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the south relative to the ground. What is the bird's velocity relative to the ground? State your answer to one decimal place
can be solved using pythagoras theorem
r^2=o^2+a^2
r^2=5.2^2+3.1^2
r^2=36.65
r=6.1km/hr is te birds velocity relative to the ground
tanz=5.2/3.1
z=tan^-1(5,2/3.1)
z=59.1 degree to the horizontal
Answer:
It can be replicated and verified.
(c) is correct option.
Explanation:
Given that,
The following statements about a pseudoscientific idea.
(a). It is biased in its results.
(b). It can be tested and observed.
(c). It can be replicated and verified.
(d). It is improved with new information.
We know that,
Pseudo science :
In a pseudoscience, such as statements, trusts and facts about whom it is said these are scientific and logical but these statements is anomalous through the scientific method.
So, we can say that the statement is true about a pseudoscientific idea that is It can be replicated and verified
Hence, It can be replicated and verified.
(c) is correct option.
<span>the heated filament will react with the oxygen in the air but now with the argon, which is a noble gas and hardly ever reacts.</span>
Answer:
The volume of the submerged part of her body is 
Explanation:
Let's define the buoyant force acting on a submerged object.
In a submerged object acts a buoyant force which can be calculated as :
ρ.V.g
Where ''B'' is the buoyant force
Where ''ρ'' is the density of the fluid
Where ''V'' is the submerged volume of the object
Where ''g'' is the acceleration due to gravity
Because the girl is floating we can state that the weight of the girl is equal to the buoyant force.
We can write :
(I)
Where ''W'' is weight
⇒ If we consider ρ = 
(water density) and 
and replacing this values in the equation (I) ⇒
ρ.V.g = 610N
(II)
The force unit ''N'' (Newton) is defined as
Using this in the equation (II) :
We find that the volume of the submerged part of her body is
