If an object accelerating at −1.5m/s^2 takes 1.2s to reach 5.0m/s, what was its initial speed?
1 answer:
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Answer:
<h2>The angular velocity just after collision is given as</h2><h2>Explanation:
As per given figure we know that there is no external torque about hinge point on the system of given mass
So here we will have
now we can say
so we will have
Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass
So we can use angular momentum conservation about the hinge point
Answer:
8.59 rad/s
Explanation:
Given that:
A thin uniform cylindrical turntable radius = 2.7 m
with a mass (M) = 22 kg
initial angular speed (ω₁) = 12 rad/s
Mass of the clump of the clay (m) = 11 kg
Diameter (d) from the point of rotation = 1.7 m
We are to find the final angular velocity (ω₂) ,To do that; we apply the conservation of annular momentum; which is as follows:
L₁ = L₂
l₁ω₁ = l₂ω₂
( 0.5 × M × r²) × ω₁ = (0.5 × M × r² + md²) ω₂
Making ω₂ the subject of the formula ; we have:
Hence, the angular speed of the clay and turntable = 8.59 rad/s