Answer:
The  kinetic energy is 
Explanation:
From the question we are told that 
        The  radius of the orbit is  
        The gravitational force is  
The kinetic energy of the satellite is mathematically represented as 
        
where v is the speed of the satellite which is mathematically represented as 
      
=>  
substituting this into the equation 
       
Now the gravitational force of the planet is mathematically represented as 
       
Where M is the mass of the planet and  m is the mass of the satellite 
  Now looking at the formula for KE we see that we can represent it as 
      ![KE  =  \frac{ 1}{2} *[\frac{GMm}{r^2}] * r](https://tex.z-dn.net/?f=KE%20%20%3D%20%20%5Cfrac%7B%201%7D%7B2%7D%20%2A%5B%5Cfrac%7BGMm%7D%7Br%5E2%7D%5D%20%2A%20r)
=>    
substituting values 
        
          
  
 
        
             
        
        
        
B explanation : they are both filled to the same pint
        
             
        
        
        
Answer:
D lower energy waves is most likely the safest if one is exposed to.
 
        
             
        
        
        
Explanation:
At the instant of release there is no force but an acceleration of a, this means the ball is falling freely under the force of gravity. Then the acceleration would be due to force of gravity and acceleration a = g =9.81 m/s^2.
g= acceleration due to gravity
 
 
        
             
        
        
        
Answer
Integral EdA = Q/εo =C*Vc(t)/εo = 3.5e-12*21/εo = 4.74 V∙m <----- A)
Vc(t) = 21(1-e^-t/RC) because an uncharged capacitor is modeled as a short.
ic(t) = (21/120)e^-t/RC -----> ic(0) = 21/120 = 0.175A <----- B)
Q(0.5ns) = CVc(0.5ns) = 2e-12*21*(1-e^-t/RC) = 30.7pC
30.7pC/εo = 3.47 V∙m <----- C)
ic(0.5ns) = 29.7ma <----- D)