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2 years ago

According to the wave-mechanical model of the atom, electrons are located in

Chemistry

2 answers:

Anon25 [30]2 years ago

4 0

The nucleus im pretty sure

Citrus2011 [14]2 years ago

3 0

The nucleus I’m positive

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Milk of magnesia has the chemical formula Mg(OH)2. What is the mass of 3.2 moles of milk of magnesia? The molar Mass of magnesiu

GenaCL600 [577]

To calculate the mass of milk of magnesia given, we need certain data like molar mass of the compound which needs the atomic mass of the atoms in the compound. We calculate as follows:

Molar mass of Mg(OH)2 = 24.3 g/mol + (2 x (16 + 1.0)) = 58.30 g/mol

Mass = 3.2 mol (58.30 g/mol) = 186.56 grams

3 0

3 years ago

A sample of water at 100°C is converted to steam after absorbing 820 kJ of heat. How grams of H2O are contained in the sample? A

Varvara68 [4.7K]

Since water is already at 100°C all the energy is used to evaporate it.
Now we can calculate how many mols of water are evaporated with 820kJ.
$N= \frac{820}{41} =20 mol$
We calculated that we got 20 mols of water evaporated. Now, all we have to do is find how many grams is a mol of water. Molar mass of water is 20.16 g/mol.
The final answer is:
$m=20*20.16=403.2g$

7 0

3 years ago

Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.

BaLLatris [955]

Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = 240.9

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

Mr of (O₃)₃ = (16 × 3) × 3 = 144

Now we can find percentage composition / percentage by mass of oxygen.

% composition = $\frac{Mr\ of\ oxygen\ in\ compound}{Mr\ of\ compound}$ × 100

% composition = $\frac{144}{240.9}$ × 100 = 59.776%

∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).

8 0

2 years ago

6. Why does the sun seem to change position in the sky?

Dafna11 [192]

A. Earth’s Rotation

4 0

3 years ago

A. Convert the mass of the Salt weighed out to fg.

omeli [17]

Answer:

6.564×10¹⁶ fg.

Explanation:

The following data were obtained from the question:

Mass of beaker = 76.9 g

Mass of beaker + salt = 142.54 g

Mass of salt in fg =?

Next, we shall determine the mass of the salt in grams (g). This can be obtained as follow:

Mass of beaker = 76.9 g

Mass of beaker + salt = 142.54 g

Mass of salt =?

Mass of salt = (Mass of beaker + salt) – (Mass of beaker)

Mass of salt = 142.54 – 76.9

Mass of salt = 65.64 g

Finally, we shall convert 65.64 g to femtograms (fg) as illustrated below:

Recall:

1 g = 1×10¹⁵ fg

Therefore,

65.64 g = 65.64 g × 1×10¹⁵ fg / 1g

65.64 g = 6.564×10¹⁶ fg

Therefore, the mass of the salt is 6.564×10¹⁶ fg.

3 0

3 years ago