Answer:
10 neutrons
Explanation:
N=Z-A ie. number of neutrons=mass number-atomic number
N=19-9=10
Answer:
The two ways to measure mass are subtraction and taring.
Answer:
Brainliest pls
Explanation:
1 mole of a substance contains Avagadro’s number of particles,
i.e. 6.023*10^23
By unitary method,
5 moles of oxygen contains 5 times the Avagadro’s number of particles
i.e. 5* (6.023*10^23) = 3.0115*10^24 number of particles.
Now, the further answer depends on what particles the question concentrates on.
If number of atoms are asked , the above answer must be multiplied by 2, because oxygen is a diatomic gas and each atom contributes to be a particle.
therefore, 5 moles of oxygen has 6.023*10^24 atoms.
If number of molecules asked, the above answer is directly written...
Answer:
Explanation:
C) What is the multiplicity of Proton-alpha's signal in this scenario when there are 2 identical protons "next door"?
Based on n+1 rule. Here n=2 (identical beta protons).
2+1=3
So the multiplicity of alpha proton is triplet, .
D) For molecules containing only single bonds (we'll discuss the influence of double bonds in a future lecture), what is the adjective that describes the position of protons that split a "next door neighbor's" signal?
The meaning of the adjective is this: the multiplicity of beta protons is singlet only (no spliting) in absence of alpha proton . But beta protons splits as doublet (n=1) in the presence of alpha proton,
E) How many bonds connect these "splitting next door neighbors"?
There are 3 bonds in between alpha and beta protons in a molecule.
F) What is the multiplicity of the Proton-betas' signal?
Following the n+1 rule, here n=1 (1 alpha proton) so 1+1=2. Hence it is a doublet.
<h3>
Answer:</h3>
150000 J
<h3>
General Formulas and Concepts:</h3>
<u>Chemistry</u>
<u>Thermodynamics</u>
Specific Heat Formula: q = mcΔT
- <em>q</em> is heat (in J)
- <em>m</em> is mass (in g)
- <em>c</em> is specific heat (in J/g °C)
- ΔT is change in temperature (in °C or K)
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>m</em> = 225 g
[Given] <em>c</em> = 4.184 J/g °C
[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C
[Solve] <em>q</em>
<u>Step 2: Solve for </u><em><u>q</u></em>
- Substitute in variables [Specific Heat Formula]: q = (225 g)(4.184 J/g °C)(159.8 °C)
- Multiply: q = (941.4 J/°C)(159.8 °C)
- Multiply: q = 150436 J
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
150436 J ≈ 150000 J
Topic: AP Chemistry
Unit: Thermodynamics
Book: Pearson AP Chemistry
