What is the symbol for voltage? A. p B. V C. I D. v

Use the images to explain why carbon forms a bond with four chlorine atoms.

lina2011 [118]

Explanation:

The Lewis dot diagram shows how electrons participate in a bond with Carbon and Chlorine. This is shown by the sticks and the 2 paired electrons near the carbon atom which represent the bonds. These electrons form these bonds because they form octets when they are bonded which most molecules and compounds follow

Hoped this helped, 2Trash4U

5 0

3 years ago

Read 2 more answers

Composition of the nuclei of two atomic species A and B are given below:

Inessa [10]

Explanation:

(a) mass number = atomic number + number of neutrons

(the atomic number is the number of protons of an element)

mass number of A = 11 + 12 = 23

mass number of B = 17 + 18 = 35

(b) +1 and -1, respectively

(c) A+ + B- → AB (the first plus sign and the minus sign are superscripts)

5 0

2 years ago

In the following equation,

Nina [5.8K]

It is C It is C It is C

3 0

3 years ago

If a Ferrari with an initial velocity of 10m/s accelerates at a rate of 5m/s2 for 3 seconds. What will it’s final velocity be?

Reika [66]

Answer:

V = 25 m/s

Explanation:

From first equation of motion, V = U + at

V = 10 + ( 5×3 )

V = 25 m/s

4 0

3 years ago

When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°

dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.30^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant =

m= molality = $\frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579$

$8.30^0C=1\times K_f\times 0.579$

$K_f=14.3^0C/m$

Let Mass of solute (KBr) = x g

$8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}$

$x=58.2g$

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

7 0

2 years ago