What influence do culture and customs have on beliefs about mental disorders? Customs really don't determine what is considered
1 answer:
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Answer:
The magnitude of the friction force exerted on the box is 2.614 newtons.
Explanation:
Since the box is sliding on a rough horizontal floor, then it is decelerated solely by friction force due to the contact of the box with floor. The free body diagram of the box is presented herein as attachment. The equation of equilbrium for the box is:
(Eq. 1)
Where:
- Kinetic friction force, measured in newtons.
- Mass of the box, measured in kilograms.
- Acceleration experimented by the box, measured in meters per square second.
By applying definitions of weight () and uniform accelerated motion (
), we expand the previous expression:
And the magnitude of the friction force exerted on the box is calculated by this formula:
(Eq. 1b)
Where:
- Weight, measured in newtons.
- Gravitational acceleration, measured in meters per square second.
- Initial speed, measured in meters per second.
- Final speed, measured in meters per second.
- Time, measured in seconds.
If we know that ,
,
,
and
, the magnitud of the kinetic friction force exerted on the box is:
The magnitude of the friction force exerted on the box is 2.614 newtons.
Answer:
A)
B)
Explanation:
Given:
mass of car,
A)
frequency of spring oscillation,
We knkow the formula for spring oscillation frequency:
Now as we know that the springs are in parallel and their stiffness constant gets added up in parallel.
<u>So, the stiffness of each spring is (as they are identical):</u>
B)
given that 4 passengers of mass 70 kg each are in the car, then the oscillation frequency:
Answers:
a)
b)
Explanation:
a) Since we are told the satellites circle the space station at constant speed, we can assume they follow a uniform circular motion and their tangential speeds are given by:
(1)
Where:
is the angular frequency
is the radius of the orbit of each satellite
is the period of the orbit of each satellite
Isolating :
(2)
Applying this equation to each satellite:
(3)
(4)
(5)
(6)
(7)
(8)
Ordering this periods from largest to smallest:
b) Acceleration is defined as the variation of velocity in time:
(9)
Applying this equation to each satellite:
(10)
(11)
(12)
(13)
(14)
(15)
Ordering this acceerations from largest to smallest:
1) 5.5 N
When the ball is at the bottom of the circle, the equation of the forces is the following:
where
T is the tension in the string, which points upward
mg is the weight of the string, which points downward, with
m = 0.158 kg being the mass of the ball
g = 9.8 m/s^2 being the acceleration due to gravity
is the centripetal force, which points upward, with
v = 5.22 m/s being the speed of the ball
R = 1.1 m being the radius of the circular trajectory
Substituting numbers and re-arranging the formula, we find T:
2) 3.9 N
When the ball is at the side of the circle, the only force acting along the centripetal direction is the tension in the string, therefore the equation of the forces becomes:
And by substituting the numerical values, we find
3) 2.3 N
When the ball is at the top of the circle, both the tension and the weight of the ball point downward, in the same direction of the centripetal force. Therefore, the equation of the force is
And substituting the numerical values and re-arranging it, we find
4) 3.3 m/s
The minimum velocity for the ball to keep the circular motion occurs when the centripetal force is equal to the weight of the ball, and the tension in the string is zero; therefore:
and re-arranging the equation, we find