Explanation:
Value of the cross-sectional area is as follows.
A = 
= 3.45 
The given data is as follows.
Allowable stress = 14,500 psi
Shear stress = 7100 psi
Now, we will calculate maximum load from allowable stress as follows.
= 
= 50025 lb
Now, maximum load from shear stress is as follows.
= 
= 48990 lb
Hence, 
will be calculated as follows.
= 48990 lb
Thus, we can conclude that the maximum permissible load is 48990 lb.
Answer:
For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
Explanation:
Force = (mass) x (acceleration)
If the full 15N is pointing parallel to the ground,
then
15 N = (58 kg) x (acceleration).
Divide each side
by 58 kg: Acceleration = 15 N / 58 kg
= (15 kg-m/s²) / (58 kg)
= (15/58) (kg-m/kg-s²)
= 0.26 m/s² .
Answer:
Displacement = 70 m towards east
Explanation:
Displacement is the shortest distance between the two points.
Let us say that he starts at the point O and travels in a path ABC.
If we join the initial and final point of the path travelled by him, it will give the displacement of the man.
Distance from O to A = 40 m
Distance from A to B = 70 m
Distance from B to C = 40 m
Distance from O to A = Distance from B to C
We want the displacement which is distance between the points O and C
In rectangle opposite sides are equal. Hence Distance from O to C = Distance from A to B
Displacement = Distance from A to B
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Answer:
(a) θ = 55.85 degree
(b) 7.89 km
Explanation:
Using vector notations
A = 1.88 km south = 1.88 (- j) km = - 1.88 j km
B = 9.05 km 47 degree north of east
B = 9.05 ( Cos 47 i + Sin 47 j) km
B = (6.17 i + 6.62 j) km
Net displacement is
D = A + B
D = - 1.88 i + 6.17 i + 6.62 j = 4.29 i + 6.62 j
(a) Angle made with positive X axis
tanθ = 6.62 / 4.29 = 1.474
θ = 55.85 degree
(b) distance = 
distance = 7.89 km
