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Tanzania [10]
3 years ago
9

Kinetic energy has this unit?​

Physics
1 answer:
Kobotan [32]3 years ago
3 0
Heres your great lovley answer that you need

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In which electric circuit would the voltmeter read 10 volts ?
ki77a [65]

Given that,

Voltage = 10 volt

Suppose, The three resistance is connected in parallel and each resistance is 12 Ω. find the current in the electric circuit.

We need to calculate the equivalent resistance

Using formula of parallel

\dfrac{1}{R}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}

Put the value into the formula

\dfrac{1}{R}=\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}

\dfrac{1}{R}=\dfrac{1}{4}

R=4\ \Omega

We need to calculate the current in the circuit

Using ohm's law

V=IR

I=\dfrac{V}{R}

Where, V = voltage

R = resistance

Put the value into the formula

I=\dfrac{10}{4}

I=2.5\ A

Hence, The current in the circuit is 2.5 A

4 0
3 years ago
The tires of a car make 75 revolutions as the car reduces its speed uniformly from 95 km/hr to 55 km.hr. the tires have a diamet
sveta [45]
<span>95 km/h = 26.39 m/s (95000m/3600 secs) 55 km/h = 15.28 m/s (55000m/3600 secs) 75 revolutions = 75 x 2pi = 471.23 radians radius = 0.80/2 = 0.40m v/r = omega (rad/s) 26.39/0.40 = 65.97 rad/s 15.28/0.40 = 38.20 rad/s s/((vi + vf)/2) = t 471.23 /((65.97 + 38.20)/2) = 9.04 secs (vf - vi)/t = a (38.20 - 65.97)/9.04 = -3.0719 The angular acceleration of the tires = -3.0719 rad/s^2 Time is required for it to stop (0 - 38.20)/ -3.0719 = 12.43 secs How far does it go? 65.97 - 38.20 = 27.77 M</span>
7 0
3 years ago
In a football game, a 90 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vi
irinina [24]

To solve this problem it is necessary to apply the equations related to the conservation of momentum. Mathematically this can be expressed as

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where,

m_{1,2}= Mass of each object

v_{1,2} = Initial velocity of each object

v_f= Final Velocity

Since the receiver's body is static for the initial velocity we have that the equation would become

m_2v_2 = (m_1+m_2)v_f

(0.42)(21) = (90+0.42)v_f

v_f = 0.0975m/s

Therefore the velocity right after catching the ball is 0.0975m/s

8 0
3 years ago
Higher levels of co2 are more likely to be found where on the earth? question 15 options: uniformly around the globe as winds bl
AlladinOne [14]
Uniformly around the globe. it is mostly found in earths atmosphere. 
5 0
3 years ago
PLEASE HELP
lawyer [7]

I SAID don’t copy from internet but u did

Explanation:

5 0
3 years ago
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