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Tanzania [10]
4 years ago
9

Kinetic energy has this unit?​

Physics
1 answer:
Kobotan [32]4 years ago
3 0
Heres your great lovley answer that you need

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A lead ball is dropped 30 feet from a church tower. If the acceleration due to gravity is 9.8m s^-2, how long does it take the b
Alika [10]

<em>fina</em><em>l</em><em> </em><em>velo</em><em>city</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>falli</em><em>ng</em><em> </em><em>obj</em><em>ect</em><em> </em><em>=</em><em> </em><em>0</em>

<em>and</em><em> </em><em>accel</em><em>eration</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>falli</em><em>ng</em><em> object</em><em> </em><em>is</em><em> </em><em>nega</em><em>tive</em>

<em>now</em><em> </em><em>usi</em><em>ng</em><em> </em><em>the</em><em> </em><em>exp</em><em>ression</em><em> </em><em>(</em><em> </em><em>Newton's</em><em> </em><em>3</em><em>r</em><em>d</em><em> </em><em>eq</em><em>uation</em><em> </em><em>of</em><em> </em><em>mo</em><em>tion</em><em>)</em>

<em>{v}^{2}  =  {u}^{2}  - 2gs</em>

<em>wher</em><em>e</em><em> </em><em>the</em><em> </em><em>para</em><em>meters</em><em> </em><em>ha</em><em>ve</em><em> </em><em>the</em><em>ir</em><em> </em><em>usu</em><em>al</em><em> </em><em>meaning</em>

<em>maki</em><em>ng</em><em> </em>

<em>{u}^{2}  \: the \: subject</em>

<em>thus</em><em> </em>

<em>{u}^{2}  = 2gs</em>

<em>u =  \sqrt{2gs}</em>

<em>from</em><em> </em><em>the</em><em> </em><em>question</em><em>,</em><em> </em>

<em>g</em><em>=</em><em> </em><em>9</em><em>.</em><em>8</em><em>m</em><em>/</em><em>s^</em><em>2</em>

<em>s</em><em> </em><em>=</em><em> </em><em>3</em><em>0</em><em>m</em>

<em>sub</em><em>stitute</em><em> </em><em>the</em><em>m</em><em> </em><em>in</em><em>to</em><em> </em><em>th</em><em>e</em><em> equation</em>

<em>u =  \sqrt{2(9.8 \times 30)}</em>

<em>u =  \sqrt{588}</em>

<em>u</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em>.</em><em>2</em><em>5</em><em>m</em><em>/</em><em>s</em>

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<em>so</em><em> </em><em>sub</em><em>stitute</em><em> </em><em>them</em><em> </em><em>in</em><em> </em><em>the</em>

<em>Newton's</em><em> first</em><em> </em><em>eq</em><em>uation</em><em> </em><em>of</em><em> </em><em>motion</em>

where

V = u - gt

but from the question,

v= 0 and the acceleration is negative because it's a free fall

substitute the values into the equation

0 = 24.24 -9.8t

making t the subject

9.8t = 22.24

dividing through by 9.8

9.8t/9.8 = 22.24/9.8

t = 2.3s . therefore, it would take 2.3s for the ball to hit the ground.

4 0
4 years ago
A wooden disk of mass m and radius r has a string of negligible mass is wrapped around it. If the disk is allowed to fall and th
Tju [1.3M]

Answer:

a = \frac{2}{3}g

T = \frac{mg}{3}

Explanation:

As the disc is unrolling from the thread then at any moment of the time

We have force equation as

mg - T = ma

also by torque equation we can say

TR = I\alpha

TR = \frac{1}{2}mR^2(\frac{a}{R})

T = \frac{1}{2}ma

Now we have

mg - \frac{1}{2}ma = ma

mg = \frac{3}{2}ma

a = \frac{2}{3}g

Also from above equation the tension force in the string is

T = \frac{1}{2}ma

T = \frac{mg}{3}

7 0
4 years ago
What are the set of equations called that can be used to quantify motion in the case of uniform acceleration?
KATRIN_1 [288]
The kinematic equations are used to <span>quantify motion in the case of uniform acceleration.

The other name is : SUVAT equations, where the letters signify: 
 displacement (s),
initial velocity (u),
 final velocity (v),
acceleration (a), and
 time (t).

There are three equations are attached in the picture: </span>

7 0
4 years ago
An observer notes that the pitch of a sound is becoming progressively higher.the observer can conclude that the sound is moving
Dahasolnce [82]
The observer can conclude that the sound is moving away from them and that its speed is increasing.
6 0
4 years ago
If a person walks 3 blocks East, turns and walks 5 blocks north. The person then turns and walks 3 blocks west and then 5 blocks
torisob [31]
The person still walked 16 blocks but ended up in the same spot he started from
3 0
3 years ago
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