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Semmy [17]
3 years ago
10

What species would you domesticate?

Chemistry
1 answer:
pav-90 [236]3 years ago
3 0
Oooooooo cheetahhhhhhh
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A sample of oxygen gas occupies a volume of 160 liters at 364 K. What will be the volume of the gas when the temperature drops t
Ivahew [28]

Answer:

62L

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tysm.

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hope it help

8 0
3 years ago
How many iron atoms contained in a 0.83 mole sample of iron
xxMikexx [17]

Answer: 5.00 x 10^23 atoms

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of Iron = 6.02 x 10^23 atoms

0.83 moles of Iron = Z atoms

To get the value of Z, cross multiply:

Z atoms x 1mole = (6.02 x 10^23 x 0.83)

Z = 5.00 x 10^23 atoms

Thus, there are 5.00 x 10^23 atoms of iron.

4 0
3 years ago
Is migration a long term consequence for competitive exclusion
stepan [7]

long term consequence, not many can come back from it


5 0
3 years ago
Watching the assignment without knowing how to solve the questions is the worst thing to experience hope someone can help with t
frez [133]

Answer:

- 622.5kJ

Explanation:

1)      2NH3 + 3N2O ----> 4N2 + 3H2O    ΔH° 1= - 1010kJ

-  3 (N2O  + 3H2     --->  N2H4 + H2O    ΔH° 2 = - 317 kJ)

2)      2NH3 + 3N2O ----> 4N2 + 3H2O        ΔH° 1= - 1010kJ

<u>      - 3N2O   - 9 H2     ----> - 3N2H4 - 3H2O      - 3ΔH° 2 = 3*317 kJ</u>

2NH3  + 3N2H4 --->4N2+9H2,     ΔH° 1 -  3*ΔH° 2

2NH3  + 3N2H4  --->4N2+9H2,        ΔH° 1 -  3*ΔH° 2

3) -(2NH3 +1/2O2 ---> N2H4 + H2O,     ΔH°3 = -143 kJ)

   -2NH3 - 1/2O2 ---> - N2H4 - H2O,    - ΔH°3 = 143 kJ

 2NH3  + 3N2H4 --->4N2+9H2,        ΔH° 1 -  3*ΔH° 2

<u>  -2NH3 - 1/2O2              ---> - N2H4 - H2O,             - ΔH°3 = 143 kJ</u>

 4N2H4 + H2O  ---> 4N2  + 9H2 + 1/2O2,    ΔH° 1 -  3*ΔH° 2 - ΔH°3

4)

H2 + 1/2O2 ---> H2O,    ΔH° 4 = - 286 kJ

9*(H2 + 1/2O2 ---> H2O,    ΔH° 4 = - 286 kJ)

9H2+ 9/2 O2 ---> 9H2O,  9*ΔH° 4 = 9*(- 286) kJ

4N2H4 + H2O  ---> 4N2  + 9H2 + 1/2O2,    ΔH° 1 -  3*ΔH° 2 - ΔH°3

<u>9H2+ 9/2 O2    ---> 9H2O,                             9*ΔH° 4 = 9*(- 286) kJ</u>

4N2H4 +4O2 --->4N2+8H2O,         ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4

5)

1/4*(4N2H4 +4O2 --->4N2+8H2O,    ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4

N2H4 +O2 --->N2+2H2O,        1/4( ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)

6)

N2H4 +O2 --->N2+2,        

1/4( ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)=

=1/4(-1010kJ - 3*(-317kJ) - (-143kJ) + 9*(-286kJ))= - 622.5 kJ

   

7 0
3 years ago
Identify What are the charges on ions of Group 1A,<br> Group 3A (aluminum), and Group 5A?
dalvyx [7]

Explanation:

 Group 1A         +1

 Group 3A         +3 or +1

 Group 5A         +5 or +3

The charges on an ion signifies the number of electrons that has been lost, gained or shared by an atom. These electrons are called valence electrons occupying the outermost shell of an atom.

 Group 1A element will readily be willing to lose an electron giving them a charge of +1

  Group 3A can lose either 1 or 3 electrons giving a charge of +3 or +1

  Group 5A can lose either 5 or 3 electrons giving a charge of +5 or +3

The number of lost electron confers the stability on the configuration.

Learn more:

Charges brainly.com/question/8849218

#learnwithBrainly

4 0
3 years ago
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