Answer:
They decrease did the problem
Explanation:
did already if it helps can i have brain pls?
Answer:
b) carboxylic acid ..........
55.4 because that's how much one particle has
<span>Answer:
Mass % KCL:
Add the grams of both compounds (31.0 g KCL + 225 g water) to find total mass and then divide the grams of KCL over the total mass, then multiply by 100: ( 31.0 g KCL / 31.0 g + 225 G) * 100%
Mole fraction KCL
Calculate the moles of KCL and water and add them to find the total moles (Moles of KCL + moles of water). Then, divide the number of KCL moles over the total moles.
moles of KCL/ moles kcl + moles water= mole fraction of KCL</span>
Each particle has two possibilities: either it is on the left hand side or it is on the right hand side.
The probability of having them equally split is
P(100,100) = 200C100 / 2^200
where 200C100 is the binomial coefficient.
For the uneven distribution we have
P= 2 * 200C160 / 2^200
where the factor 2 comes in because we could have 160/40 or 40/160 as a division.
So the ratio of probabilities is
200C100 /(2 * 200C160 )
= 2.2 * 10^16
Hope this helps!
