Answer:
The answer to your question is V2 = 3.7 L
Explanation:
Data
Volume 1 = 3.5 L
Temperature 1 = 25°C
Temperature 2 = 40°C
Pressure = cte.
Volume 2 = ?
Formula
To solve this problem use the Charles' law
V1/T1 = V2/T2
- Solve for V2
V2 = V1T2 / T1
- Convert temperature to °K
Temperature 1 = 25 + 273 = 298°K
Temperature 2 = 40 + 273 = 313°K
- Substitution
V2 = (3.5)(313) / 298
- Simplification
V2 = 1095.5 / 298
- Result
V2 = 3.7 L
Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Explanation:
First we have to calculate the moles of diethyl ether

As, 1 mole of diethyl ether require heat = 26.5 kJ
So, 1.01 moles of diethyl ether require heat = 
Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
I'm pretty sure that you multiply the number of moles by avogadro's number (6.02x10^23)... you may want to check.
Observe a blue light be wavelength flame test during
Answer:
<h3>3.2 millions years old</h3>
Explanation:
i hope it helps :)