Missing question: A possible atomic weight of Q is?
A)12.7.
B)19.0.
C)27.5
D)38.0
E)57.0.
Answer is: possible atomic weight of Q is B) 19.0.
Molecular weight of first molecule is 38.0 g/mol.
Molecular weight of second molecule is 57.0 g/mol.
Molecular weight of third molecule is 76.0 g/mol.
Molecular weight of fourth molecule is 114.0 g/mol.
All four molecular weights can be division only by 19 to get whole number:
Molecule 1 (38 ÷ 19 = 2), molecule 2 (57 ÷ 19 = 3), molecule 3 (76 ÷ 19 = 4) and molecule 4 ( 114 ÷ 19 = 6).
Molecular formulas are than Q₂, Q₃, Q₄ and Q₆.
CaCO₃ + 2HCl = CaCl₂ + CO₂ + H₂O
n(CaCO₃)=m(CaCO₃)/M(CaCO₃)
n(CaCO₃)=13.00/100.09=0.1299 mol
Δm=13.00+52.65-60.32=5.33 g
m(CO₂)=5.33 g
n(CO₂)=5.33/44.01=0,1211 mol
w=0.1211/0.1299=0,9323 (93.23%)
Answer:
1s^22s^22p^63s^23p^64s^23d^104p^4
Answer:
I should use a volumetric flask.
Explanation:
If the accuracy of the concentration is important, we need to use a volumetric flask.
