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Elena L [17]
3 years ago
13

(2x-1) (3x+5) -(2x-1) (x+4)

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Answer:

4x^2−1

Step-by-step explanation:

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12). In 1991, there were an estimated 235 fish in a lake. In 1996, there were 134
weqwewe [10]

Answer:bless you

Step-by-step explanation:

4 0
3 years ago
HELP DUE IN 15 MINS!<br><br> x=??
ad-work [718]

Answer:

Step-by-step explanation:

Remark

The angle formed by the intersection of a tangent to a circle and an intersecting secant is 1/2 (Arc PS - arc PR)

PS = 208

PR = 74

Solution

x = 1/2 (208 - 74)

x = 1/2 (134)

x = 67

4 0
3 years ago
1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg
tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

d=\sqrt{x^2+y^2}

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute  :

d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}

d=1\ km

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20

Thus we have

x.x'+y.y'=20

Solving for x'

\displaystyle x'=\frac{20-y.y'}{x}

Since y'=-60

\displaystyle x'=\frac{20+0.6(60)}{0.8}

x'=70\ km/h

The SUV is running at 70 km/h

7 0
3 years ago
Birthstones of students in your class<br> qualitative Or quantitative??
Alik [6]
Quantitive since it can be counted
3 0
3 years ago
Find the missing lengths of the sides
dusya [7]

Answer:

a=9, c=19

Step-by-step explanation:

Aight so basically in 30, 60, 90 triangles there is a formula for the sides

the hypotenuse(the longest side)=2a

The tiny side (the smallest side)=a

and the middle child =a\sqrt{3}

Based on that we see that a is 9

and since c=2a then it's 18

4 0
3 years ago
Read 2 more answers
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