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DochEvi [55]
2 years ago
14

What is an effect of gravity on objects on the surface of Earth? Check all that apply.

Chemistry
2 answers:
Flauer [41]2 years ago
9 0

Answer: The correct statements are:

  • Objects “fall” toward the center of Earth.
  • Objects accelerate at a rate of 9.8 m/s each second.
  • Objects are pulled by Earth more strongly than they pull on Earth.

Explanation:

The gravity of the earth is the force which attracts the object to the center of the earth. When the any object with mass falls under the action of the gravity attains the acceleration of 9.8 m/s^2.

  • Objects “fall” toward the center of Earth.
  • Objects accelerate at a rate of 9.8 m/s each second.
  • Objects are pulled by Earth more strongly than they pull on Earth.
dexar [7]2 years ago
6 0

Answer:

options 1 and 3 are correct. Objects “fall” toward the center of Earth. Objects accelerate at a rate of 9.8 m/s each second.

Explanation:

The reason option 5 is false is because of Newton's Third Law, stating that for every action, there is an equal and opposite reaction. So the action and reaction forces by the Earth and the object are equal to one another.

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Bess [88]

Answer:

Explination:

Given Data:

                  Trail 1          Trial 2         Trial 3

Student A 448.0 cm 485.6 cm 463.4 cm

Student B 450.5 cm 441.3 cm         446.8 cm

Student C 422.6 cm 445.2 cm 432.7 cm

Accepted Value = 435.0 cm

Required:

A: Accurate measurement =?

B: Reason for the answer =?

C: Precise measurement =?

D: Reason for the answer =?

Solution:

Student A:

Trail 1: 435.0 cm – 448.0 cm = (13.0 cm greater than accepted value)

Trail 2: 435.0 cm – 485.6 cm = (50.6 cm greater than accepted value)

Trial 3: 435.0 cm – 463.4 cm = (28.4 cm greater than accepted value)

Student B:

Trail 1: 435.0 cm – 450.5 cm = (14.5 cm greater than accepted value)

Trail 2: 435.0 cm – 441.3 cm = (6.3 cm greater than accepted value)

Trial 3: 435.0 cm – 446.8 cm = (11.8 cm greater than accepted value)

Student C:

Trial 1: 435.0 cm – 422.6 cm = (12.4 cm less than accepted value)

Trial 2: 435.0 cm – 445.2 cm = (10.2 cm greater than accepted value)

Trial 3: 435.0 cm – 432.7 cm = (1.3 cm less than accepted value)

A: The 3rd trial of the student C is accurate measurement = 432.7 cm.

B: The 3rd value of students’ C measurement is accurate because it is quite near to the accepted value, i.e.  435.0 cm.

As we know that Accuracy refers to the closeness of a measured value to a standard or known value.

This value has only the difference of 1.3 cm.

435.0 cm – 432.7 cm = (1.3 cm less than accepted value)

All the other have larger difference which is as above.

___________________

Student A:

1. 448.0 cm – 485.6 cm = (37.6 cm far)

2. 485.6 cm – 463.4cm = (22.2 cm far)

Student B:

1. 450.5 cm – 441.3 cm = (9.2 cm far)

2. 441.3 cm – 446.8 cm = (5.5 cm far)

Student C:

1. 422.6 cm – 445.2 cm = (22.6 cm far)

2. 445.2 cm – 432.7cm = (12.5 cm far)

So,

C: The values of Student B are more precise.

D: As we know that Precision refers to the closeness of two or more measurements to each other.

The measurements of student C are more close to each other. The values are only 9.2 cm and 5.5 cm far from each other.

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3 years ago
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Answer:

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Explanation:

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