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DochEvi [55]
3 years ago
14

What is an effect of gravity on objects on the surface of Earth? Check all that apply.

Chemistry
2 answers:
Flauer [41]3 years ago
9 0

Answer: The correct statements are:

  • Objects “fall” toward the center of Earth.
  • Objects accelerate at a rate of 9.8 m/s each second.
  • Objects are pulled by Earth more strongly than they pull on Earth.

Explanation:

The gravity of the earth is the force which attracts the object to the center of the earth. When the any object with mass falls under the action of the gravity attains the acceleration of 9.8 m/s^2.

  • Objects “fall” toward the center of Earth.
  • Objects accelerate at a rate of 9.8 m/s each second.
  • Objects are pulled by Earth more strongly than they pull on Earth.
dexar [7]3 years ago
6 0

Answer:

options 1 and 3 are correct. Objects “fall” toward the center of Earth. Objects accelerate at a rate of 9.8 m/s each second.

Explanation:

The reason option 5 is false is because of Newton's Third Law, stating that for every action, there is an equal and opposite reaction. So the action and reaction forces by the Earth and the object are equal to one another.

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Hydrogen sulfide,H2S, is a very toxic gas with a smell of rotten eggs. using the following: H2S+3/2 O2=SO2+H2O H2+1/2O2=H2O S+O2
Serga [27]

Answer:

ΔH = -20kJ

Explanation:

The enthalpy of formation of a compound is defined as the change of enthalpy during the formation of 1 mole of the substance from its constituent elements. For H₂S(g) the reaction that describes this process is:

H₂(g) + S(g) → H₂S(g)

Using Hess's law, it is possible to sum the enthalpies of several reactions to obtain the change in enthalpy of a particular reaction thus:

<em>(1) </em>H₂S(g) + ³/₂O₂(g) → SO₂(g) + H₂O(g) ΔH = -519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

The sum of -(1) + (2) + (3) gives:

<em>-(1) </em>SO₂(g) + H₂O(g) → H₂S(g) + ³/₂O₂(g) ΔH = +519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

<em>-(1) + (2) + (3): </em><em>H₂(g) + S(g) → H₂S(g) </em>

<em>ΔH =</em> +519kJ - 242kJ - 297kJ = <em>-20 kJ</em>

<em />

I hope it helps!

5 0
3 years ago
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Answer:

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Explanation:

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snow,sleet is the answer

Explanation:

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