If you are graphing quadratic equations of the type
ax^2 + bx + c = 0
The equation will look like a "U" <span>if "a" is positive </span>or it will look like an upside-down "U" <span>if "a" is negative </span>
Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
yo dont click that link hes a scammer thats an ip grabber
Find A <span>if B is between A and C.
</span><span>A.B,and C are collinear so A, B and C are line up in a line</span>
AC = AB + BC
AB=5x-19,and BC= 3x+4 given;
So
AC = 5x-19 + 3x+4
Simplify
AC = 8x -15
