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Anna007 [38]
3 years ago
11

Help me !!!! please thanks so much

Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer:

what's the question please

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A rocket is launched into the air. The height h(t), in yards, of the rocket is a function of time, t, in seconds, as shown in th
Vesna [10]

Answer:

Step-by-step explanation:

Average rate of change is the same thing as the slope.  Because this is parabolic, we cannot find the exact rate of change as we could if this were a linear function.  But we can use the same idea.  When t = 3, h(t) = 33, so the coordinate point is (3, 33).  When t = 6, h(t) = 0, so the coordinate is (6, 0).  Plug those values into the slope formula:

m=\frac{0-33}{6-3} and

m=\frac{-33}{3} which is -11

From 3 to 6 seconds, the rocket is falling 11 yards per second.

8 0
4 years ago
ZP bisects ∠OZQ so that ∠OZP = 8x – 9 and ∠PZQ = 5x + 18. Find the value of x, and the measure of each angle. You must show all
Assoli18 [71]
<span>x = 9 Since ZP bisects â OZQ, that means that the measurements for â OZP and â PZQ are the same. So create an equation with their respective values set to each other. 8x - 9 = 5x + 18 Now solve for x 8x - 9 = 5x + 18 Subtract 5x from both sides 3x - 9 = 18 Add 9 to both sides 3x = 27 Divide both sides by 3 x = 9</span>
6 0
3 years ago
Gas station X charges $4.00 per gallon of gas. Gas station Y charges $4.12 per gallon of gas. What is the percent increase from
kirill [66]
First, find the increase in charge between the two station. That is:

$4.12-$4.00=$0.12

Then, divide the increase by the price charged by Gas Station X.

$0.12/$4.00=0.03

Lastly, since it is a decimal, transform it to percentage by multiplying 100%

0.03x100%=3%

Hope this is the brainliest answer.
3 0
3 years ago
Please help me with this!!
nydimaria [60]

Answer:

Step-by-step explanation:

these triangles are not similar,  you can tell, b/c the one given angle and that they are both right triangles, so you also know that the other angle , that is not given is not the same, in the two.   hence the sides are not the same lengths or ratios of each other.  they are NA

6 0
3 years ago
At t=0, a rock is dropped from rest from the top of a building 256 ft high. With what velocity will it strike the ground? What i
Rasek [7]

Answer:

128 ft / second.

Step-by-step explanation:

It's acceleration is due to gravity and is 32 ft s^-2.

To find the velocity when it hits the ground we use the equation of motion

v^2 = u^2 + 2gs    where  u = initial velocity, g = acceleration , s = distance.

v^2 = 0^2 + 2 * 32 * 256

v^2 = 16384

v =  128 ft s^-1.

4 0
4 years ago
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