Cells are considered the smallest part of an organsim that can?

Newer aircraft jet catapult systems use magnets instead of steam. The launch still takes 1.19 seconds, but the acceleration is a

Westkost [7]

Answer:

33.6 m

Explanation:

Given:

v₀ = 0 m/s

a = 47.41 m/s²

t = 1.19 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (1.19 s) + ½ (47.41 m/s²) (1.19 s)²

Δx = 33.6 m

8 0

2 years ago

*A car is going through a dip in the road whose curvature approximates a circle of radius 150m. At what velocity will the occupa

Valentin [98]

Answer:

v= 14.85 m/s

Explanation:

When at the bottom of the dip, the only force that keeps the car in the circular trajectory, is the centripetal force.
This force is not a new force, is just the net force aiming to the center of the circle.
In this case, is just the difference between the normal force (always perpendicular to the surface, pointing upward) and the force that gravity exerts on the car (which is known as the weight), pointing downward.
So, we can write the following expression:

$F_{cent} = F_{n} - F_{g} (1)$

It can be showed that the centripetal force is related to the speed by the following expression:
$F_{cent} = m*\frac{v^{2}}{r} (2)$

The normal force, it is called the apparent weight, because it would be the weight as measured by a scale.
Replacing (2) in (1), and solving for Fn, we get:

$F_{n} = m*\frac{v^{2} }{r} + m*g (3)$

Now, we need to find the value of v that makes Fn, exactly 15% more than the weight m*g, so we can write the following equation:

$F_{n} = 1.15*F_{g} = m*\frac{v^{2}}{r} +F_{g} (4)$

Replacing Fg by its value, simplifying, and solving for v, we get:

$v = \sqrt{0.15*g*r} = \sqrt{9.8 m/s2*0.15*150m} = 14.85 m/s (5)$

3 0

2 years ago

Assume that the turntable deccelerated during time Δt before reaching the final angular velocity ( Δt is the time interval betwe

Zina [86]

Answer:

See below...

Explanation:

Let’s express ⟨α⟩ in terms of ωi , ωf , and Δt. and torque in terms of It , ωi , ωf , and Δt.

STEP 1.

The rate of change of angular velocity is Angular acceleration.

The net change in angular velocity is Average angular acceleration divided by the elapsed time.

⟨α⟩ = ω f −ω i/Δt

STEP 2.

Torque is assumed this way

dω

τ = I ----

dt

.

⟨τ ⟩ = I t (ω f −ω i )/Δt

6 0

3 years ago

A constant magnetic field passes through a single rectangular loop whose dimensions are 0.35 m × 0.55 m. The magnetic field has

Pani-rosa [81]

Answer:

Part a)

$EMF = 0.38 V$

Part b)

$\frac{dA}{dt} = 0.43 m^2/s$

Explanation:

Part a)

Initial value of magnetic flux is given as

$\phi_1 = BAcos\theta$

$\phi_1 = (2.1)(0.35 \times 0.55) cos65$

so we have

$\phi_1 = 0.17 Wb$

Final flux through the loop is given as

$\phi_2 = 0$

now EMF is given as

$EMF = \frac{\phi_1 - \phi_2}{\Delta t}$

$EMF = \frac{0.17 - 0}{0.45}$

$EMF = 0.38 V$

Part b)

If magnetic field is constant while Area is changing

So EMF is given as

$E = Bcos65 \times \frac{dA}{dt}$

$0.38 = 2.1 cos65(\frac{dA}{dt})$

$\frac{dA}{dt} = 0.43 m^2/s$

5 0

2 years ago

Jody does long distance running and also strength trains twice a week.

murzikaleks [220]

Answer:

Jody will have strong bones and show muscle hypertrophy. 

Explanation:

Long distance running practiced regularly helps in increasing the strength of bones. Muscular hypertrophy is the increase in mass of skeletal muscles due to the increase in the size of myofibrils or increase in muscle glycogen storage. Strength training exercises performed regularly induce muscular hypertrophy.

During strength training exercises muscles undergo contraction and repeated contraction breaks muscle fibres. New muscle fibres are added as a means of repair and this happens at the relaxing phase of muscles. More muscle fibres are added to compensate the damage and thus muscle mass increases. 

6 0

2 years ago

Cells are considered the smallest part of an organsim that can?​

Cells are considered the smallest part of an organsim that can?