Cells are considered the smallest part of an organsim that can?

In a given chemical reaction, the energy of the products is greater than the energy of the reactants. Which statement is true fo

Flura [38]

Energy is released in the reaction

Explanation:

In a given where the energy of the products is greater than that of the reactants, we can infer that energy is released in the reaction.

This indicates that the reaction is an exothermic or exergonic reaction.

These reaction types are accompanied by release of energy.

In an exothermic change energy is released to the surroundings.
The surrounding becomes hotter at the end of the change.
This applies in exergonic reaction which leaves a reaction having more energy than it originally started with.

Learn more:

Exothermic process brainly.com/question/10567109

#learnwithBrainly

3 0

3 years ago

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1. How many paths through which charge can flow would be shown in a diagram of a series

Elanso [62]

1. One
2. Oohm

Hope this helps

5 0

3 years ago

A wheel initially spinning at wo = 50.0 rad/s comes to a halt in 20.0 seconds. Determine the constant angular acceleration and t

svetlana [45]

Answer:

(I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.

(II). The torque is 84.87 N-m.

Explanation:

Given that,

Initial spinning = 50.0 rad/s

Time = 20.0

Distance = 2.5 m

Mass of pole = 4 kg

Angle = 60°

We need to calculate the angular acceleration

Using formula of angular velocity

$\omega=-\alpha t$

$\alpha=-\dfrac{\omega}{t}$

$\alpha=-\dfrac{50.0}{20.0}$

$\alpha=-2.5\ rad/s^2$

The angular acceleration is -2.5 rad/s²

We need to calculate the number of revolution

Using angular equation of motion

$\theta=\omega_{0}t+\dfrac{1}{2}\alpha t$

Put the value into the formula

$\theta=50\times20-\dfrac{1}{2}\times2.5\times20^2$

$\theta=500\ rad$

The number of revolution is 500 rad.

(II). We need to calculate the torque

Using formula of torque

$\vec{\tau}=\vec{r}\times\vec{f}$

$\tau=r\times f\sin\theta$

Put the value into the formula

$\tau=2.5\times4\times 9.8\sin60$

$\tau=84.87\ N-m$

Hence, (I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.

(II). The torque is 84.87 N-m.

8 0

3 years ago

How does a bimetallic strip work in a sinple alarm system

tatiyna

The bimetallic strip in a fire alarm is made of two metals with different expansion rates bonded together to form one piece of metal. Typically, the low-expansion side is made of a nickel-iron alloy called Invar, while the high-expansion side is an alloy of copper or nickel. The strip is electrically energized with a low-voltage current. When the strip is heated by fire, the high-expansion side bends the strip toward an electrical contact. When the strip touches that contact, it completes a circuit that triggers the alarm to sound. The width of the gap between the contacts determines the temperature that will set off the alarm.

7 0

2 years ago

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Calculate the wave number for the infrared absorption of D35Cl when there is a transition from v=0 to v=1 (Unit: cm^-1, 4-digit

AVprozaik [17]

Answer:

wave number = 0.3348 * 10⁻⁸ cm⁻¹

Explanation:

Given data:

K = 4.808 * 10^2 N/m

<u>Determine the wave number for the infrared absorption</u>

considering vibrational Spectre

k' = 2n / λ ---- ( 1 )

λ = c / v ----- ( 2 )

v = √k / u --- ( 3 )

where : k' = wave number, λ = wavelength, c = velocity of light, v = frequency, k = force constant, u = reduced mass

u = 1.90415 for D35Cl

Input equations 2 and 3 into equation 1 to get the final equation

K' = 2n/c * √k / u

= ( 2 * 3.14 ) / 2.98 * 10^8 ] * (√ 4.808 * 10^2 / 1.90415 )

= 33.486 * 10⁻⁸ m⁻¹ ≈ 0.3348 * 10⁻⁸ cm⁻¹

6 0

3 years ago

Cells are considered the smallest part of an organsim that can?​

Cells are considered the smallest part of an organsim that can?