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krek1111 [17]
2 years ago
7

How you would go about separating a mixture of salt and sand. Knowing that salt will dissolve in water. Device a method to separ

ate the mixture.
Materials required: funnel, filter paper, beaker, 250 mL Erlenmeyer flask, mixture of salt and sand
Chemistry
1 answer:
DanielleElmas [232]2 years ago
8 0

Separating a mixture of salt and sand will involve two main techniques such as filtration and evaporation.

<h3>What is Filtration?</h3>

This is a technique which is used to separate a fluid from a solid matter such as sand etc.

Since salt dissolves in the water, the fluid is collected using the filter paper placed inside the funnel. After which it enters the Erlenmeyer flask and is heated to allow for evaporation of water and collection of the salt.

Read more about Filtration here brainly.com/question/23945157

#SPJ1

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Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?
german

Answer : The correct option is, (A) AlCl_3

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) AlCl_3

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of AlCl_3 will be,

AlCl_3\rightarrow Al^{3+}+3Cl^{-}

So, Van't Hoff factor = Number of solute particles = Al^{3+}+3Cl^{-} = 1 + 3 = 4

(B) KI

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of KI will be,

KI\rightarrow K^{+}+I^{-}

So, Van't Hoff factor = Number of solute particles = K^{+}+I^{-} = 1 + 1 = 2

(C) CaCl_2

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^{-}

So, Van't Hoff factor = Number of solute particles = Ca^{2+}+2Cl^{-} = 1 + 2 = 3

(D) MgSO_4

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of MgSO_4 will be,

MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}

So, Van't Hoff factor = Number of solute particles = Mg^{2+}+SO_4^{2-} = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, AlCl_3

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3 years ago
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500

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from the average and if yoy multiple and then add your % and x you would get 500 to 600

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The answer is b.

Hope that helps :)
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If a chemical reaction goes to completion, what can we say about the equilibrium constant for that reaction?
aniked [119]

Answer:

A. The equilibrium constant is very large

Explanation:

The equilibrium constant value is the ratio of the concentrations of the products over the reactants. When a chemical reaction goes to completion, that means that all the reactant has turned into products. As the equilibrium constant defines, it is the ratio of the product to the reactant. So at the final stage of the chemical reaction, the equilibrium constant will be very large.

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What 100 plus 124000
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100 + 124000 = 124100
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