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valkas [14]
3 years ago
12

How much ammonia would it take to neutralize 5ml of apple cider and 5ml of white vinegar if the ammonia had a molarity of 0.25?

Chemistry
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer:

m_{NH_3}=0.0213gNH_3

Explanation:

Hello there!

In this case, since it is known that the reaction between ammonia and acetic acid is:

CH_3COOH+NH_3\rightarrow CH_3COONH_4

It is possible for us to realize that the mole ratio of acetic acid (vinegar) to ammonia is 1:1, that is why we can relate the concentrations as follows:

M_{acid}V_{acid}=M_{base}V_{base}\\\\

In such a way, by knowing that the volume of these two are the same, we infer that their concentrations is also de same; and therefore, the mass of ammonia is calculated as:

m_{NH_3}=0.005L*0.25\frac{molNH_3}{L}*\frac{17.04gNH_3}{1molNH_3}\\\\m_{NH_3}=0.0213gNH_3

Regards!

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Answer:

m_{C_6H_5Cl}=65.7gC_6H_5Cl

Explanation:

Hello!

In this case, according to the given balanced chemical reaction:

C_6H_6 (l) + Cl_2 (g) \rightarrow C_6H_5Cl (s) + HCl (g)

We can see there is 1:1 between benzene and chlorobenzene as the relavant product; thus, since the molar mass of benzene is 78.11 g/mol and that of chlorobenzene is 112.55 g/mol, the theoretical yield for this reaction turns out:

m_{C_6H_5Cl}=45.6gC_6H_6*\frac{1molC_6H_6}{78.11gC_6H_6 }*\frac{1molC_6H_5Cl}{1molC_6H_6}*\frac{112.55gC_6H_5Cl}{1molC_6H_5Cl}   \\\\m_{C_6H_5Cl}=65.7gC_6H_5Cl

Best regards!

8 0
3 years ago
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posledela

Answer:

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Explanation:

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Answer:

Hi there!

Your answer is:

A.

Explanation:

When frozen, water turns from a liquid to a solid! An example of this is a glass of water. You fill the glass with liquid tap water, and then put ice cubes in it. The ice cubes are solid and the tap water is liquid!

I hope this helps!

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