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Marina86 [1]
3 years ago
9

Jeremy had a set of 500 toy blocks that could be connected by snapping them together. At first, he used all the blocks to build

a small house. Later, he rearranged all the blocks to build a small car. How did the mass of the house compare to the car?
Chemistry
2 answers:
valentina_108 [34]3 years ago
6 0
The masses were the same
Nat2105 [25]3 years ago
3 0

Answer:

The masses were the same.

Explanation:

study isalnd :)

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Differences between alkalis, bases and acids? (answer for many points :) )
Rudik [331]

Explanation:

protons.

An acid can also be thought of as a chemical that can neutralize a base. Similarly, a base can neutralize an acid.

Acids turn litmus paper red, while bases make litmus paper turn blue.

Some examples of acids are sulfuric acid, hydrochloric acid, nitric acid, and so on. Some examples of bases are sodium hydroxide, potassium hydroxide, and so on.

Acids generally taste sour, while bases have a bitter taste.

Alkalis are the bases that are water-soluble, which means that they dissolve in water. In other words, not all bases are water-soluble, and only the water-soluble bases are known as alkalis. An example of an alkali is sodium hydroxide. It is a base because it can neutralize an acid, and because it is water-soluble, it is an alkali. An example of a base that is not alkali is copper oxide. This chemical can neutralize an acid, but it is insoluble in water.

In other words, all alkali are bases but not all bases are alkalis.

Also, an alkali has a hydroxide group, while a base has an oxide group in it.

3 0
2 years ago
What is white light?
PSYCHO15rus [73]

White light is when red, orange, and yellow are absorbed.

8 0
2 years ago
Match Term Definition
mart [117]

The correct answers are:

1. Lithium - C) Opaque solid with higher density

2. Lead - B) Malleable, soft, and shiny

3. Florine - D) Highly reactive gas

4. Krypton - A) Nonreactive gas

I hope that helps u!

:)


7 0
3 years ago
This particle determines what element you have - the element's identity.
scoundrel [369]

Answer:

protons

These particles do not vary in quality from one element to another; rather, what gives an element its distinctive identification is the quantity of its protons, called its atomic number. Protons and neutrons contribute nearly all of an atom's mass; the number of protons and neutrons is an element's mass number

Explanation:

4 0
3 years ago
You take three compounds consisting of two elements and decompose them. To determine the relative masses of X, Y, and Z, you col
miss Akunina [59]

Answer:

a) LAW OF MULTIPLE PROPORTIONS

b) 0.095g, 0.71g, 0.285g respectively

c) X2Y, YZ15, X6Y

d) hence mass of compound X = 21 x 0.045 = 0.95g

mass of compound Y = 21 x 0.955 = 20.05g

Explanation:

a) The assumptions made in solving this questions is the application of the LAW OF MULTIPLE PROPORTIONS. The Law of multiple proportions states that if two elements A and B combine together to form more than one compound, then the several masses of A which chemically combine with a fixed mass of B is in a simple ratio.

for example, copper forms two oxides ; copper(I) oxide (CuO) and copper(ii) oxide(Cu2O), it is possible for the two samples of the oxides to be reduced to Cu by reacting with Hydrogen gas. as such, certain masses of oxygen combine separately with a fixed mass of Cu. then the ratios of Cu are then determined.

b) To calculate the relative masses, we take note of the three compounds given, they all have some amount of Y in them, hence we can use Y  as our relative mass, this implies that the relative mass of Y = 1g

mass of X = 0.4g

mass of Y = 4.2g

amount of X in 1g of Y = 0.4 x 1 /4.2

= 0.095g

for compound 2;

mass of Y = 1.4g

mass of Z = 1.0g

amount of Z in 1g of Y =1.0 x 1 /1.4

= 0.71g

for compound 3;

mass of X = 2.0g

mass of Y = 7.0g

amount of X in 1g of Y = 1 x 2/7

= 0.285g

c) Applying the law of multiple proportions; since elements X and Z combine with a fixed mass of Y, they must bear a simple ratio;

compound 1/compound 3 = 0.095/0.285

= 1/3

compound 1/compound 2 = 0.095/0.71

= 2/15

compound 2/ compound 3 = 0.71/0.285

= 5/2

formular for compound 1 = X2Y

formula for compound 2 = YZ15

formular for compound 3 = X6Y

d) from the formular X2Y, we can get the amount of each product in XY using the ratios

%of compound XY in X = mass of compound X / total Mass

= 0.2/4.4 = 4.5%

as such in a 21g of compound XY, %of compound Y = 1 - %of compound X = 95.5%

hence mass of compound X = 21 x 0.045 = 0.95g

mass of compound Y = 21 x 0.955 = 20.05g

5 0
3 years ago
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