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Damm [24]
3 years ago
11

Why do different materials/objects have different reactions to fire?​

Chemistry
2 answers:
elena-s [515]3 years ago
7 0
The more oxygen molecules that collide per second with the fuel, the faster the combustion reaction is and that’s how it could be so different
True [87]3 years ago
5 0

Answer:

Different compounds react with oxygen differently – some contain lots of heat energy while others produce a smaller amount. The reaction with the oxygen may happen very quickly or more slowly. Amount: The amount of fuel available to burn is known as the fuel load.

Explanation:

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Please answer the following on the picture<br>ASAP PLZZZ
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30. Atomic Number is 17

31. Chlorine

32. 35.45

33. Nonmetal

34. 3 energy levels

35. 7 Valence electrons

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4 years ago
Which statement best describes a difference between scientists and engineers?
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Answer. Answer: Scientists study how things work, while engineers create new things
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A.<br> B.<br> C.<br> D.<br><br> Help me please?
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3 years ago
Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine
dolphi86 [110]

Answer:

The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

            pKb1 = - log [kb]

                5.1  = - log [kb]

                take Antilog of both side

             [kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

           From the question, 1900 ml of solution contains 1 g of Q

           Therefore,  1000 ml of solution will contain........... x g of Q

           x = 1000 /1900

           x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

                                         = 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

            At Equilibrium, Kb = x² / 0.0016

            7.94 x 10∧-6 = x² / 0.0016

            x = √ 0.0016 × 7.94 x 10∧-6

            x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4:  Calculating the pH of Quinine

           Recall, pOH = - log [OH-]

           pOH = - log [1. 127 × 10∧-4]

           pOH = 3.948

           Also recall that pH + pOH = 14

           pH = 14 - 3.948

           pH = 10.05

           

8 0
4 years ago
How can you chose values for x when making a table of values representing a real world situation?
Nitella [24]
X is usually representing time so years, days, etc
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