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ratelena [41]
3 years ago
8

Calculate the pH of the solution: [OH-] = 1x10^-11M a.11.0 b.12.0 c.2.7 d.3.0

Chemistry
1 answer:
Veronika [31]3 years ago
6 0

p [OH-] = -log[OH-]= -log ( 1x10^-11M) = 11

we know that

p[OH-] + p[H+] = 14

so p[H+] = 14- p[OH-] = 14- 11 = 3

pH = 3, answer

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