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photoshop1234 [79]
4 years ago
12

A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10

s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 1.5 rad/s2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to:
A) 17 s B) 15 s C) 19 s D) 21 s E) 23 s
Physics
2 answers:
Sergeeva-Olga [200]4 years ago
6 0
I have some notes here that might help you answer the problem on your own:

<span>α = <span>dω / <span>dt

</span></span></span>Angular acceleration is derivative of angular velocity the same way as linear acceleration is derivative of linear velocity<span>
a = <span>dv / <span>dt

I hope my answer has come to your help. God bless and have a nice day ahead!</span></span></span>
rodikova [14]4 years ago
3 0
Hello there.

<span>A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 1.5 rad/s2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to:

</span><span>A) 17 s</span>
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