A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10
s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 1.5 rad/s2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to: A) 17 s B) 15 s C) 19 s D) 21 s E) 23 s
I have some notes here that might help you answer the problem on your own:
<span>α = <span>dω / <span>dt
</span></span></span>Angular acceleration is derivative of angular velocity the same way as linear acceleration is derivative of linear velocity<span> a = <span>dv / <span>dt
I hope my answer has come to your help. God bless and have a nice day ahead!</span></span></span>
<span>A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 1.5 rad/s2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to:
