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Tanya [424]
2 years ago
10

An object of mass M is placed on a disk that can rotate. One end of a string is tied to the object while the other end of the st

ring is held by a pole that is located at the center of the disk. Initially, the object is spun in a horizontal circle of radius R at a constant tangential speed of v0, as shown in the figure, such that the tension in the string is T. At a later time, the disk is spun such that the tangential speed of the object is increased to 2v0 . At a later time, the tangential speed of the object is increased to 3v0 . Which of the following diagrams could represent the forces exerted on the object at one of the given speeds? Assume that the force of static friction is negligible. Select two answers.
2T
3T
4T
9T
Physics
2 answers:
Mars2501 [29]2 years ago
7 0

Answer:

Graphic labeled 4t and graphic labeled 9t

polet [3.4K]2 years ago
6 0

Answer: 4t and 9t

Explanation:

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Answer:

his movement is proportional to the intensity of the earthquake,

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An earthquake is a record of the intensity of an earthquake as a function of time.

Where the intensity is plotted on the y-axis, which corresponds to the vertical movement of the detector, this movement is proportional to the intensity of the earthquake, therefore the intensity increases the amplitude of the oscillation increases.

And the in x corresponds to time

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What is the thickness of the disk of the milky way?
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4 years ago
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Hope this helps!

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4 0
3 years ago
Develop a hypothesis for why one of the two types of soup should indeed be rolling down faster than the other. This hypothesis s
Eva8 [605]

Answer:

Assume two identical cans filled with two types of soup having same mass are rolling down on an inclined plane in same conditions. In terms of inertia different types of soup will indicate different viscosity. The higher viscosity fillings indicates more part of the soup mass is rotating together with the can’s body. This means that for the can with lower viscosity soup has a lower moment of inertia and the can with higher viscosity has higher moment of inertia while the same gravity makes them to roll.

incline angle = θ ; can's mass =  m ; Radius of the can's = R , Angular acceleration for Can 1 = α1 ; Angular acceleration for Can 2 = α2

T1 = Inertia of Can with high viscosity soup

T2 = Inertia of Can with low viscosity soup

M1 rolling moment of Can 1

M2 rolling moment of Can 2

equation is given by

T1*α1 = M1   - (a)

T2*α2 = M2 - (b)

M1 = M2 = m*g*R*sin(θ). (c)

as assumed T1 > T2

from the three equation (a), (b) & (c)

the α2 > α1

Angular acceleration of Can 2 is higher than Can 1. Already stated that Can 1 has more viscous soup as compared to Can 2.

7 0
3 years ago
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