Ask question

Ask question

All categories

3 years ago

6

I need help thank you

1 answer:

NISA [10]3 years ago

8 0

The correct answer is PB

You might be interested in

Mary spent $100 for $150 worth of merchandise. What percentage did she save?

ankoles [38]

66.6% because 100 is 2/3rds of 150

5 0

3 years ago

Read 2 more answers

Please help me solve this

andrew-mc [135]

A function assigns the values. The value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

Given p(x)= x²+5x, therefore, the value of (p·p)(x) can be written as,

(p·p)(x) = p(p(x))

= (x²+5x)²+5(x²+5x)

= x⁴ + 25x² + 10x³ + 5x² + 25x

= x⁴ + 10x³ + 30x² + 25x

Hence, the value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

4 0

2 years ago

Plz help me I need it by 10

Ostrovityanka [42]

He will be on team 3

Student# 1 2 3 4 5 6 7 8 9 10 11
Team# 1 2 3 4 1 2 3 4 1 2 3

5 0

3 years ago

WILL MARK BRAINIEST!!! Segment AC has two endpoints; (-2,5) and (2,-5). What are the coordinates of point B on segment AC such t

svet-max [94.6K]

Answer:

$(\frac{4}{3},-\frac{10}{3})$

Step-by-step explanation:

If the extreme ends of a line segment AC are A $(x_1,y_1)$ and C $(x_2,y_2)$ .

If a point B(x, y) divides the segment in the ratio of m : n

Then the coordinates of the point B are,

x = $\frac{mx_2+nx_1}{m+n}$

y = $\frac{my_2+ny_1}{m+n}$

If the ends of AC are A(-2, 5) and C(2, -5) and a point B divides it in the ratio of m : n = 5 : 1

Therefore, coordinates of this point will be,

x = $\frac{5\times (2)+1(-2)}{5+1}$

= $\frac{10-2}{5+1}$

= $\frac{8}{6}$

= $\frac{4}{3}$

y = $\frac{5\times (-5)+1(5)}{5+1}$

= $\frac{-25+5}{6}$

= $-\frac{20}{6}$

= $-\frac{10}{3}$

Therefore, coordinates of the point B are $(\frac{4}{3},-\frac{10}{3})$ .

6 0

3 years ago

What is the complete factorization of the polynomial function over the set of complex numbers? f(x)=x^3+3x^2+16x+48

Tamiku [17]

Answer: $(x+3)(x+4i)(x-4i)$ is the required factorization of f(x).

Step-by-step explanation:

To factor the expression we must first group the terms and then take out common from these groups

$f(x)=x^3+3x^2+16x+48=(x^3+3x^2)+(16x+48)$

Taking $x^2$ common from first group and the 16 from second group we get:

$f(x) = x^2(x+3)+16(x+3) = (x+3)(x^2+16)$

Now, to factor in complex from we have to break term $x^2+16$

$f(x)= (x+3){x^2-(-4i)^2}$

As, $i^2 = -1 , therefore (-4i)^2 = 16i^2 =-16$

Also using identity $a^2-b^2 =(a+b)(a-b)$

On solving

$f(x) = (x+3)(x+4i)(x-4i)$

$(x+3)(x+4i)(x-4i)$ is the required factorization of f(x).

8 0

3 years ago