Answer: Object distance is : 20cm
Explanation:
Given the following :
Magnification (m) = - 1.50
Image Distance from lens (v) = 30cm
Calculate the object distance (u) :
Recall:
Magnification = - [image distance (v) / object distance (u)]
Therefore, Inputting our values :
-1.50 = - (30 / u)
1.50 * u = 30
u = 30 / 1.50
u = 20 cm
Answer:
9 meters
Explanation:
Given:
Mass of Avi is, 
Spring constant is, 
Compression in the spring is, 
Let the maximum height reached be 'h' m.
Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.
So, by law of conservation of energy, decrease in elastic potential energy is equal to increase in gravitational potential energy.
Decrease in elastic potential energy is given as:

Now, increase in gravitational potential energy is given as:

Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,

Therefore, Avi will reach a maximum height of 9 meters.
12kN is equal to 12000 N
and the perpendicular component will be
[email protected] mg = 12000 N
cos10°= 0.984
thus it will be 12000*0.984 = 11808N
the frictional force will be
[email protected]sin10° = 0.1736
and hence it will be = 2083N
Does that help I hope IT does you probably just have to write the 1st sentence.