It is most accurate to say that body mass index (BMI) provides information about an individual's height-weight ratio. The correct answer is B.
Answer:
Explanation:
<u>Vertical Launch Upwards</u>
In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.
If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:
The object referred to in the question is thrown from a height H=0 and the maximum height is hm=77.5 m.
(a)
To find the initial speed we solve for vo:
(b)
The maximum time or the time taken by the object to reach its highest point is calculated as follows:
Answer:
The correct answer is - Damage to the nerves that control the diaphragm.
Explanation:
Abdominal breathing is a condition in which inferior half of the lungs can be seen relaxing or contracting and expanding with the breath. This condition occurs due to the various conditions that lead to the respiratory.
It is cause due to the damage to nerves that control the diaphragm. The phrenic nerve is one of the nerve of diaphragm initiates in the neck and passes down.
Thus, the correct answer is - Damage to the nerves that control the diaphragm.
The phrenic nerve is a nerve that originates in the neck (C3–C5) and passes down between the lung and heart to reach the diaphragm.
The answer is 4.0 kg since the flywheel comes to rest the
kinetic energy of the wheel in motion is spent doing the work. Using the
formula KE = (1/2) I w².
Given the following:
I = the moment of inertia about the
axis passing through the center of the wheel; w = angular velocity ; for the
solid disk as I = mr² / 2 so KE = (1/4) mr²w². Now initially, the wheel is spinning
at 500 rpm so w = 500 * (2*pi / 60) rad / sec = 52.36 rad / sec.
The radius = 1.2 m and KE = 3900 J
3900 J = (1/4) m (1.2)² (52.36)²
m = 3900 J / (0.25) (1.2)² (52.36)²
m = 3.95151 ≈ 4.00 kg
Answer:
50.97 m
Explanation:
m = Mass of truck
= Coefficient of static friction = 0.4
v = Final velocity = 0
u = Initial velocity = 72 km/h = 
s = Displacement
Force applied
Frictional force
Now these forces act opposite to each other so are equal. This is valid for the case when the load does not slide
Since the obect will be decelerating the acceleration will be 
From the kinematic equations we have
So, the minimum distance at which the car will stop without making the load shift is 50.97 m.
