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NISA [10]
3 years ago
9

A measurement that has both magnitude and direction

Physics
1 answer:
Korvikt [17]3 years ago
7 0
<span>A measurement that both magnitude and direction is a vector quantity. An example of this is a moving car. The car exerts force due to its thrust and weight that runs in it. This will give us the magnitude of the car. The resulting motion of the car in terms of displacement, velocity and acceleration that determines its direction makes it a vector quantity. On the other hand, a measurement that has only magnitude is a scalar quantity. The energy exerted by the engine of the car is a scalar quantity.</span>
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Susan goes out to exercise. She runs for one hour at a constant speed and velocity. What is the overall net force acting on Susa
kiruha [24]

Option (A ) is correct.

Explanation:

susan is moving with constant velocity, so both the direction and magnitude of the velocity remains same. so the acceleration of susan =0. This is because an object gets accelerated when either the magnitude or direction of the speed changes.

now the force is given by

F= ma

F= force

m= mass

a= acceleration

Here a =0

so F= 0

so the net force on susan is zero.

3 0
3 years ago
Read 2 more answers
Examine the lightbulbs in the circuit below. Write a sentence explaining what would happen if lightbulb A burned out. Repeat thi
tatiyna

If the lightbulb A in the circuit shown in the image burned out, the path for the  current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.

If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.

8 0
4 years ago
Which describes a force acting on an object?
weeeeeb [17]

Answer:

Describing a Force:

To fully describe the force acting upon an object, you must describe both its magnitude and direction. Thus, 10 Newtons of force is not a complete description of the force acting on an object. 10 Newtons, downwards is a complete description of the force acting upon an object.

Explanation:

3 0
3 years ago
If the ball leaves the projectile launcher at a speed of 2.2 m/s at an angle of 30ᴼ, and the projectile launcher is on a table a
IgorC [24]

Answer: 1.12 m

Explanation:

This situation is related to parabolic motion, hence we can use the following equations:

y=y_{o}+V_{o}sin \theta t-\frac{g}{2}t^{2} (1)

x=V_{o} cos \theta t (2)

Where:

y=0 m is the ball final height (when it hits the ground)

y_{o}=1.1 m is the ball initial height

V_{o}=2.2 m/s is the initial velocity

\theta=30\° is the angle at which the ball was launched

t is the time

g=9.8 m/s^{2} is the acceleration due gravity

x is the horizontal distance the ball travels

Rewriting (1) with the given values:

0 m=1.1 m+(2.2 m/s)(cos 30\°)t-\frac{9.8 m/s^{2}}{2}t^{2} (3)

Multiplying all the eqquation by -1 and rearranging:

4.9 m/s^{2} t^{2}-1.1 m/s t-1.1 m=0 (4)

So, since we have a quadratic equation here (in the form of0=at^{2}+bt+c,  we will use the quadratic formula to find  t:  

t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}   (5)

Where a=4.9, b=-1.1, c=-1.1  

Substituting the known values and choosing the positive result of the equation, we have:  

t=\frac{-(-1.1)\pm\sqrt{(-1.1)^{2}-4(4.9)(-1.1)}}{2(4.9)}  

t=0.59 s (6)

Now, substituting (6) in (2):

x=(2.2 m/s)(cos 30\°)(0.59 s) (7)

x=1.12 m (8) This is the horizontal distance at which the ball hits the ground.

3 0
4 years ago
Look at the potential energy diagram for a chemical reaction. Which statement correctly describes the energy changes that occur
lukranit [14]

The activation energy is 10 kJ and the reaction is exothermic.

8 0
3 years ago
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