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Citrus2011 [14]
2 years ago
15

Valence electrons are determined by the...

Chemistry
1 answer:
Marysya12 [62]2 years ago
4 0

Explanation:

A) Highest occupied energy level and Group Number.

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A metallurgical firm wishes to dispose of 1200 gallons of waste sulfuric acid whose molarity is 1.05 M. Before disposal, it will
Reil [10]

Answer:

The balanced chemical equation for this process:

H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)

$194.51 is the cost that the firm will incur from this use of slaked lime.

Explanation:

The balanced chemical equation for this process

H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)

Moles of sulfuric acid = n

Volume of sulfuric acid disposed = V = 1200 gallons = 3.785 × 1200 L = 4,542 L

1 gallon = 3.785 Liter

Morality of the sulfuric acid = M = 1.05 m

Molarity(M)=\frac{n}{V(L)}

n=m\times V=1.05 M\times 4,542 L=4,769.1 mol

According to reaction, 1 mol of sulfuric acid reacts with 1 mole of calcium hydroxide.Then 4,769.1 moles of sulfuric acid will recat with ;

\frac{1}{1}\times 4,769.1 mol=4,769.1 mol of calcium hydroxide

Mass of 4,769.1 moles of calcium hydroxide:

4,769.1 mol  74 g/mol = 352,913.4 g

= \frac{352,913.4 }{453.6} pounds =778.03 pounds

(1 pound = 453.6 grams)

Cost of 1 pound of slaked lime  = $0.25

Cost of 778.03 pounds of slaked lime  = $0.25 × 778.03 = $194.51

$194.51 is the cost that the firm will incur from this use of slaked lime.

3 0
3 years ago
What would be the volume of 0.500 mole of an ideal gas at a temperature of 273.15 Kelvins and 1 atm?
uysha [10]

Answer:

V = 11.21 L

Explanation:

Given data:

Volume of helium = ?

Number of moles = 0.500 mol

Temperature = 273.15 K

Pressure of gas = 1 atm

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

V = nRT/P

V = 0.500 mol ×  0.0821 atm.L/ mol.K  × 273.15 K / 1 atm

V = 11.21 L / 1

V = 11.21 L

8 0
3 years ago
You have two solid substances that look the same. What measurements would you take and which tests would you preform to determin
ASHA 777 [7]

Answer:

óooooooooooooo

ssssmmmmmmm

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5 0
2 years ago
Use the correct terms to explain the osmotic concentrations of the solutions.
Morgarella [4.7K]
The movement of water from lower concentration to higher concentration trough semipermeable membrane.
3 0
4 years ago
A 0.2121g sample of an organic compound was burned in a stream of oxygen and the carbon dioxide produced was collected in a stre
pav-90 [236]

Answer:

The answer to your question is: 17.26% of carbon

Explanation:

Data

CxHy = 0.2121 g

BaCO₃ = 0.6006 g

Molecular mass BaCO₃ = 137 + 12 + 48 = 197 g

Reaction

                    CO₂  +  Ba(OH)₂  ⇒   BaCO₃  +  H₂O

Process

1.- Find the amount of carbon in BaCO₃

                              197 g of BaCO₃   ---------------  12 g of Carbon

                               0.6006 g           ----------------    x

                               x = (0.6006 x 12) / 197

                               x = 0.0366 g of carbon

2.- Calculate the percentage of carbon in the organic compound

           0.2121 g of organic compound  ---------------  100%

           0.0366g                                       --------------    x

                              x = (0.0366 x 100) / 0.2121

                              x = 17.26%

4 0
3 years ago
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