I am not sure what this means? But branliest to correct answer :)
1 answer:
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<span>Determine the values of x on which the function f(x)=2x^2-x-15/4x^2-12x is discontinuous and verify the type of discontinuity at each point.
A.There is a vertical asymptote at 0 and a hole at 3.
B.There are vertical asymptotes at -5/2 & 0 and a hole at 3.
C.There is a vertical asymptote at 3 and a hole at 0.
D.There are vertical asymptotes at 0 & 3.
</span>
Result:
(-7/4)x^2-13x
The roots are:
x= -52/7
x=0
See attached pictures.
A.There is a vertical asymptote at 0 and a hole at 3.
B.There are vertical asymptotes at -5/2 & 0 and a hole at 3.
C.There is a vertical asymptote at 3 and a hole at 0.
D.There are vertical asymptotes at 0 & 3.
</span>
Result:
(-7/4)x^2-13x
The roots are:
x= -52/7
x=0
See attached pictures.
Answer:
(-4,2) belongs in this direct variation.
Step-by-step explanation:
Let the direct variation relationship is expressed by the equation y = mx ........ (1), where x and y are in direct variation and k is the variation constant.
Now, the point (4,-2) is included in the direct variation relationship, then from equation (1) we get, -2 = 4m
⇒
Therefore, the equation (1) becomes
⇒ x + 2y = 0 ......... (2)
Now, from the given four options only the point (-4,2) satisfies the relation (2).
Hence, (-4,2) belongs in this direct variation. (Answer)