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3 years ago

As light waves enter the eye, which three structures do they pass through first?

1 answer:

4 0

As light enters to the eye, it would pass first through three (3) structures or main layers/tunics:
1. Fibrous tunic - outermost layer of the eye. Consists of cornea and sclera which gives the eye white color and protect the inner parts of the eye.
2. Vascular tunic - middle layer of the eye. Consists of iris and choroid which gives the dark color of the eye and inhibits disorderly reflections inside the eye.
3. Nervous tunic - inner layer of the eye. Consist of retina which is responsible for vision

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6. If a vehicle needs 5s to complete 15m. Find the mean speed of it?

Karolina [17]

Answer:

3m/s

Explanation:

Time=5s

Distance =15m

Speed=distance/time

Putting the values

Speed=15m/5s

Speed=3m/s is the answer

Hope it will help you. :)

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3 years ago

What is the difference between work done by the gravitational force on descending and ascending objects?

Kazeer [188]

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3 years ago

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Nookie1986 [14]

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3 years ago

Read 2 more answers

Consider a traveling wave described by the formula

Harrizon [31]

Answer:

The wave is traveling in the +x direction.

Explanation:

The equation of a wave is given by the formula as :

$y(x,t)=A\ sin(kx-\omega t)$

Here,

A is the amplitude of wave

$(kx-\omega t)$ is the phase of wave

$\omega$ is the angular frequency of the wave

We need to find the correct statement out of given options. The given equation can be rewritten as :

$y(x,t)=A\ sin(\omega t-kx)$

Here, the propagation constant is negative. So, the wave is moving in +x direction. Hence, the correct option is (a).

4 0

3 years ago

The 45-g arrow is launched so that it hits and embeds in a 1.40 kg block. The block hangs from strings. After the arrow joins th

worty [1.4K]

Question: How fast was the arrow moving before it joined the block?

Answer:

The arrow was moving at 15.9 m/s.

Explanation:

The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

$\dfrac{1}{2}m_av^2 = (m_b+m_a)\Delta Hg$

where $m_a$ is the mass of the arrow, $m_b$ is the mass of the block, $\Delta H$ of the change in height of the block after the collision, and $v$ is the velocity of the arrow before it hit the block.