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yKpoI14uk [10]
3 years ago
7

What does flowing electrical charge produce?

Physics
1 answer:
Annette [7]3 years ago
6 0

Answer:

Useable energy, electricity

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The diagram shows the electric field near conducting sphere a which of the following statements is correct
Ludmilka [50]
I really don’t know but I hope this helps
4 0
3 years ago
Explain the following behaviour of molecules water rises up in a harrow tubes but mercury which is also a liquid falls in a narr
Mandarinka [93]

Answer: find the answer in the explanation

Explanation:

The capillarity of water molecules is different from the mercury molecules.

What is capillarity ?

This is the tendency of a liquid substance to rise in a capillary tube.

Molecules water rises up in a harrow tubes because of the force of adhesion between the water molecules and the tube molecules is greater than the force of cohesion between the water molecules. This helps water to wet the tube and rise. While mercury which is also a liquid falls in a narrow tubes to level below the outside surface because the force of cohesion between the mercury molecules is greater than the force of adhesion between the mercury molecules and the tube molecules. Mercury does not wet.

7 0
4 years ago
An energy plant produces an output potential of 1500 kV and serves a city 143 km away. A high-voltage transmission line carries
jekas [21]

Answer:

2123.55 $/hr

Explanation:

Given parameters are:

V_{plant} = 1500 KV

L = 143 km

I = 500 A

\rho = 2.4 \Omega / km

So, we will find the voltage potential provided for the city as:

V_{wire} =IR = I\rho L = 1500*2.4*143 = 514.8 kV

V_{city} = V_{plant}- V_{wire} = 1500-514.8 = 985.2 kV

Then, we will find dissipated power because of the resistive loss on the transmission line as:

P = I^2R = I^2\rho L=500^2*2.4*143 = 8.58*10^7 W

Since the charge of plant is not given for electric energy, let's assume it randomly as x =  \frac{\dollar 0.081}{kW.hr}

Then, we will find the price of energy transmitted to the city as:

Cost = P * x = 8.58*10^7 * 0.081 * 0.001 = 6949.8 $/hr

To calculate money per hour saved by increasing the electric potential of the power plant:

Finally,

I_{new} = P/V_{new} = I/1.2\\P_{new} = I_{new}^2R_{wire}\\Cost = P_{new}/1.44=6949.8/1.44 = 4826.25 $/hr

The amount of money saved per hour = 6949.8 - 6949.8/1.44 = 2123.55 $/hr

Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.

3 0
3 years ago
If you have a final velocity of 50 m/s and travelled for 120 seconds. What
zhuklara [117]

Answer:

a=v-u/t

Explanation:

use this formula and initial velocity is 0

5 0
2 years ago
Read 2 more answers
Help me it’s for a test I have??
Volgvan
1. C
2. A
3. E
4. D
5. B
6. F
i might have 2 and 6 mixed up, not completely sure tho
4 0
3 years ago
Read 2 more answers
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