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Likurg_2 [28]
3 years ago
11

Describing the Effects of Surfactar

Chemistry
2 answers:
krok68 [10]3 years ago
5 0

Answer:

The forces between the water molecules are called as the hydrogen bonding, while the forces of attraction between the ethanol molecules are dipole-dipole forces. Along, with the alignment or arrangement of the surface molecules makes it very clear to know more about the characteristics of the water and ethanol molecules, and the way they behave when any number of insects walk across these surfaces. So, the water characteristics makes it more easy to understand that the insects will find it more easy to walk on the surface of the water medium just because of the capacity of the molecules to with hold the amount of insects weight in a given parameter. And thus water surface is suitable for an insect to walk on rather then walking on the surface of ethanol.So, its all about the surface tension of the water medium that provides us with an option for the insect to travel on it surface.

<u>Water and ethanol two different mediums:</u>

The two different mediums represents a more different form or nature to a insect when it comes to letting it to walk over its surface. As there are different forms of bonding inside the molecules of the two different mediums, the ethanol has the dipole-dipole forces between its molecules making it much weaker to support for lifting the total weight of the insect present on its surface.

Svetlanka [38]3 years ago
3 0

Explanation:

An insect would have an easier time walking on the surface of water than on the surface of ethanol. Water's stronger intermolecular forces lead to higher surface tension. Higher surface tension allows water to support the insect. I hope this helps.

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First we have to calculate the mass of ethanol and water.

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and,

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

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c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ethanol = 35.5 g

m_2 = mass of water = 45.0 g

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T_1 = initial temperature of ethanol = 8.0^oC

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Now put all the given values in the above formula, we get:

35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC

T_f=22.14^oC

Therefore, the final temperature of the mixture is, 22.14^oC

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