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Jobisdone [24]
3 years ago
8

Which of these characteristics best describes a basic solution?

Chemistry
2 answers:
Liula [17]3 years ago
6 0
Short Answer:  <span>Solutions of dilute, weak acids - the only kind that you might taste - are sour. Weak, dilute bases are bitter. Solutions of bases are slippery.

Hope I get brainliest!</span>
yulyashka [42]3 years ago
4 0
 Solutions of bases are slippery. So in your answer sheet it should be the answer C. <span>Feels slippery.

Hope this helps !

Photon</span>
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At a certain temperature the rate of this reaction is first order in HI with a rate constant of :0.0632s
Shalnov [3]

Answer : The time taken for the reaction is, 28 s.

Explanation :

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = 0.0632

t = time taken for the process  = ?

[A_o] = initial amount or concentration of the reactant  = 1.28 M

[A] = amount or concentration left time 't' = 1.28\times \frac{17}{100}=0.2176M

Now put all the given values in above equation, we get:

0.0632=\frac{2.303}{t}\log\frac{1.28}{0.2176}

t=28s

Therefore, the time taken for the reaction is, 28 s.

8 0
3 years ago
What is the smallest division on 4 balance
tankabanditka [31]

Answer:0.1g

Explanation:

4 0
3 years ago
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What metal will have properties most similar to those of chromium (Cr)? Why?
garri49 [273]
That element is manganese. As they are in same horizontal row (period) and are next to each other. That is why they show same properties. 

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5 0
3 years ago
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SpyIntel [72]
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7 0
3 years ago
Draw the major organic product in the reaction scheme below. Be sure to clearly show stereochemistry (if applicable).
Juliette [100K]

Answer:

see explanation below

Explanation:

You are missing the reaction scheme, but in picture 1, I found a question very similar to this, and after look into some other pages, I found the same scheme reaction, so I'm gonna work on this one, to show you how to solve it. Hopefully it will be the one you are asking.

According to the reaction scheme, in the first step we have NaNH2/NH3(l). This reactant is used to substract the most acidic hydrogen in the alkine there. In this case, it will substract the hydrogen from the carbon in the triple bond leaving something like this:

R: cyclopentane

R - C ≡ C (-)

Now, in the second step, this new product will experiment a SN2 reaction, and will attack to the CH3 - I forming another alkine as follow:

R - C ≡ C - CH3

Finally in the last step, Na in NH3 are reactants to promvove the hydrogenation of alkines. In this case, it will undergo hydrogenation in the triple bond and will form an alkene:

R - CH = CH - CH3

In picture 2, you have the reaction and mechanism.

6 0
3 years ago
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