Thank you for the free 15 points .
Answer:
A) 0.95 mol
Explanation:
We will assume the gas given off in the fermentation is an ideal gas because that allows us to use the ideal gas equation.
PV = nRT
First let's convert all measurements to units that we can use
P = 702 mmHg * 1 atm/760 mmHg = 0.92368 atm
V = 25.0 L
R = 0.08206 L-atm/mol-K
T = 22.5 °C +273.15 = 295.65 K
PV = nRT
0.92368 atm * 25.0 L = n * 0.08206 L-atm/mol-K * 295.65 K
n = 0.9518 mol
The new volume is 2.4 L
<u><em> calculation</em></u>
The new volume is calculated using Boyle's law formula
That is P₁V₁=P₂V₂
where,
p₁ = 802 torr
V₁ = 12.0 l
P₂ = 4010 torr
V₂=?
make V₂ the subject of the formula by diving both side of equation by P₂
V₂ = P₁V₁/P₂
V₂ is therefore = {(12.0 l × 802 torr) 4010 torr} = 2.4 L
