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3 years ago

The Bantu were experts in this form of metallurgy. gold steel iron copper

2 answers:

4 0

they're experts in iron metallurgy

The bantu was originated from the southern part of Africa ( round republic of Congo) , and has been the expert of utilizing iron among the ancient tribe

Mostly they use it for their Agricultural system ( such as their Irrigation system, for their agricultural tools, etc)
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Karolina [17]3 years ago

4 0

Iron that the answer

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Which pair of elements form an ionic bond with

KATRIN_1 [288]

Answer:

Yes Both A) KCL and D) HCL are correct...

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2 years ago

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Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing tin

mojhsa [17]

The half reactions as they occur at each electrode

is as follows

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3 years ago

The mass of a proton is 1.00728 amu andthat of a neutron is 1.00867 amu. What is the binding energy pernucleon (in J) of a Co nu

andreyandreev [35.5K]

Answer:

The binding energy per nucleon = 1.368*10^-12 (option D)

Explanation:

<u>Step 1:</u> Data given

The mass of a proton is 1.00728 amu

The mass of a neutron is 1.00867 amu

The mass of a cobalt-60 nucleus is59.9338 amu

Step 2: Calculate binding energy

The mass defect = the difference between the mass of a nucleus and the total mass of its constituent particles.

Cobalt60 has 27 protons and 33 neutrons.

The mass of 27 protons = 27*1.00728 u = 27.19656 u

The mass of 33 neutrons = 33*1.00867 u = 33.28611 u

Total mass of protons + neutrons = 27.19656 u + 33.28611 u = 60.48267 u

Mass of a cobalt60 nucleus = 59.9338 amu

Mass defect = Δm = 0.54887 u

ΔE =c²*Δm

ΔE = (3.00 *10^8 m/s)² *(0.54887 amu))*(1.00 g/ 6.02 *10^23 amu)*(1kg/1000g)

Step 3: Calculate binding energy per nucleon

ΔE = 8.21 * 10^-11 J

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The binding energy per nucleon = 1.368*10^-12 (option D)

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3 years ago

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4 0

4 years ago

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Nitrogen dioxide is produced by combustion in an automobile engine. For the following reaction, 0.377 moles of nitrogen monoxide

Contact [7]

Answer:

The amount of NO₂ that can be produced 8.533 g

Explanation:

According to question

2 NO(g) + O₂(g) → 2 NO₂(g)

Given

Moles of nitrogen monoxide = 0.377

Moles of oxygen = 0.278

$'For NO'=\frac{Mole}{Stoichiometry}=\frac{0.377}{2} =0.1855\\'For O_{2} '=\frac{0.278}{1}= 0.278\\$

Since 'NO' is the limiting reagent according to this ratio.

According to equation

2 moles NO reacts to form 2 moles NO₂

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5 0

4 years ago