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Citrus2011 [14]
3 years ago
13

Find the x and y intercepts for the following equation. 4x - 2y = 16

Mathematics
2 answers:
Aneli [31]3 years ago
6 0
The x is (4,0)
the y is (0,-8)
irinina [24]3 years ago
4 0

Answer:

( 4, 0 ) and ( 0,-8 )

Step-by-step explanation:

→ Rearrange into y = mx + c format

4x - 2y = 16

→ Minus 4x from both sides

-2y = -4x + 16

→ Divide everything by 2

-y = -2x + 8

→ Multiply everything by -1

y = 2x - 8

→ Substitute x = 0 to find the y-intercept and y = 0 to find the x intercept

x = 0 then y = -8 so ( 0,-8 )

y = 0 then x = 4 so ( 4, 0 )

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You have to make them have the same denominator so
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Then you add them together
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You have to make it a mixed fraction.
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Juan is 1 1/4 feet shorter than maria. if maria is 1/3 foot taller than luis. if luis is 62 inches tall, how tall are maria and
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7 0
3 years ago
Suppose that 7 female and 5 male applicants have been successfully screened for 5 positions. If the 5 positions are filled at ra
katen-ka-za [31]

Answer:

(a) 350

(b) 175

(c) 21

(d) 196

Step-by-step explanation:

Number of females = 7

Number of males = 5

Total ways of selecting r items from n items is

^nC_r=\dfrac{n!}{r!(n-r)!}

(a)

Total ways of selecting 3 females and 2 males.

\text{Total ways}=^7C_3\times ^5C_2

\text{Total ways}=\dfrac{7!}{3!(7-3)!}\times \dfrac{5!}{2!(5-2)!}

\text{Total ways}=35\times 10

\text{Total ways}=350

(b)

Total ways of selecting 4 females and 1 male.

\text{Total ways}=^7C_4\times ^5C_1

\text{Total ways}=32\times 5

\text{Total ways}=175

(c)

Total ways of selecting 5 females.

\text{Total ways}=^7C_5\times ^5C_0

\text{Total ways}=21\times 1

\text{Total ways}=21

(d)

Total ways of selecting at least 4 females.

Total ways = 4 females + 5 females

\text{Total ways}=175+21

\text{Total ways}=196

6 0
3 years ago
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