Answer:
9.133×10^-6 m
Explanation:
A photon is the smallest discrete amount or quantum of electromagnetic radiation. It is the basic unit of all light. Photons are always in motion and, in a vacuum, travel at a constant speed to all observers of 3 x 10^8 m/s.
From the question, the following details were supplied;
Energy of the photon (E) = 4.61×10^−19 J
Speed of light (c) = 2.99×10^8 m/s
Plank's constant (h) = 6.626×10^−34 J⋅s
Wavelength of the photon (λ)= ??? The unknown
From
E=hc/λ
λ= hc/E
Substituting values
λ= 6.626×10^−34 × 2.99×10^8/ 4.61×10^−19
λ= 91.33×10^-7 m
λ= 9.133×10^-6 m
Hello!
The formula for Copper (II) Phosphate is
Cu₃(PO₄)₂
To know how to write this formula we go from left to right. First, Copper (II). It means that the formula has the Cu⁺² ion. Now, Phosphate means that the compound has the PO₄⁻³ ion. Now we combine this two ions, giving to each one the coefficient with the number of the electric charge of the other (e.g. to Cu⁺² we'll give the charge of PO₄⁻³ which is 3 and the result will be Cu₃⁺²).
The combination gives us the result Cu₃(PO₄)₂
Have a nice day!
First of all we should know that, 1 Joule = 0.000239 kilocalories.
So, 6.6×
J = 6.6× × 0.000239 kilocalories
6.6× J = 15774000 kilocalories
= 1.58 × 
kilocalories
One joule is described as the quantity of electricity exerted when a pressure of 1 newton is implemented over a displacement of 1 meter. Within the SI machine, the unit of labor or electricity is the Joule.
The kilocalorie, or meals calorie, is the quantity of warmth required to elevate one kilogram of water 1 °C. warmness capability is the amount of heat required to raise one gram of material 1 °C beneath steady pressure. A kilocalorie is the amount of warmth required to raise the temperature of 1 kilogram of water one diploma Celsius.
Learn more about joule here:-
brainly.com/question/490326
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