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2 years ago

11

Chlorine (CI) can be found as an ion with a 1- charge. How does this happen?

2 answers:

Lesechka [4]2 years ago

8 0

Answer:There are 18 electrons and 17 protons, so the chlorine atom has become a charged chlorine ion with a charge of negative one (-1). ... When it does, the sodium atom becomes a sodium ion with a charge of positive one (+1). Chlorine, as mentioned above, desperately wants an electron so it can fill its outer electron level.

Oduvanchick [21]2 years ago

4 0

Answer:

it gains an electron

Explanation:

a p e x :)

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CS2 + 3O2 = CO2 + 2SO2

1 mole of CS2 gives 1 mole of CO2

12 + 2(32) = 76g of CS2 yields 44 g of CO2

Theoretically 1 g of CS2 yields 44/76 g CO2

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AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

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Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

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Explanation:

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