What do you mean by specific heat capacity?

A car travels 60 miles due West first then turns back and travels 120 miles due East in 3 hours. What is...

ella [17]

Answer:

<h2>A. 180 miles</h2><h2>B. 60 miles</h2><h2 />

Explanation:

In this problem, we are required to solve for the total distance that the car travelled. and the displacement

A) the distance travelled by car

this can be gotten by summing all the distances the car has travelled.

i,e total distance= 60 miles+120 miles

total distance= 180 miles

B) the displacement of the car

the displacement can be gotten by subtracting the final distance from the initial distance

final distance = 120 miles

initial distance= 60 miles

displacement= 120-60= 60 miles

7 0

3 years ago

If the Earth rotated more slowly about its axis, your apparent weight would

disa [49]

<span>If the Earth rotated more slowly about its axis, your apparent weight would
A) increase.
B) decrease.
C) stay the same.
D) be zero.

</span>A) increase.

8 0

3 years ago

A spacecraft and a staellite are at diametrically opposite position in the same circular orbit of altitude 500 km above the eart

Tanya [424]

Answer:

Hello the diagram related to your question is attached below

answer: a) 851 m/s

b) 8506.1 secs

Explanation:

calculate the periodic time of the satellite using the equation below

t = $\frac{2\pi }{R} \sqrt{\frac{(R+h)^{3} }{g} }$ -- ( 1 )

where ; R = 6370 km

h = 500 km

g = 9.81 m/s^2

input given values into equation 1

t = 5670.75 secs

next calculate the periodic time taken by the space craft

<u>a) determine the increase in speed </u>

V = v - $\sqrt{\frac{gR^2}{R + h} }$

where ; v = 8463 m/s , R = 6370 km, h = 500 km

V = 851 m/s

b) Determine the periodic time for the elliptic orbit

τ = $\frac{3t}{2}$

= $\frac{3*5670.76}{2}$ = 8506.1 secs

attached below is the remaining part of the detailed solution

5 0

3 years ago

Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.60×106 N, one at an angle 13.0 west of north, an

Juliette [100K]

Answer: $W=1.93\times 10^9 J$

Explanation:

Given

Force $F=1.6\times 10^{6} N$

one at an angle of $13^{\circ}$ East of North and another at $13^{\circ}$ West of North

Net Force is in North Direction

$F_{net}=2F\cos 13$

Forces in horizontal direction will cancel out each other

thus Work done will be by north direction forces

$W=2F\cdot \cos 30\cdot s$

here $s=0.7 km$

$W=2\times 1.6\times 10^{6}\cdot \cos 30\cdot 700$

$W=1.93\times 10^9 J$

3 0

4 years ago

To practice problem-solving strategy 9.1 a strategy for conservation of momentum problems. an 80-kg quarterback jumps straight u

kherson [118]

Refer to the diagram shown below.

By definition momentum = mass * velocity.

Before throwing the ball:
The initial momentum is
P₁ = 0.

After throwing the ball:
Let u = the backward velocity of the quarterback.
The momentum is
P₂ = (0.43 kg)*(15 m/s) + (80 kg)*(- u m/s)

Conservation of momentum requires that
P₂ = P₁
6.45 - 80u = 0
u = 6.45/80 = 0.0806 m/s

Answer: 0.08 m/s backward

6 0

3 years ago

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What do you mean by specific heat capacity?​

What do you mean by specific heat capacity?