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2 years ago

A shopping mall is putting up lights for the holidays. When they plug the holiday lights in they do not light up.

Physics

1 answer:

mash [69]2 years ago

3 0

Answer:

Explanation:

Remark

Anybody who has dealt with Christmas Tree lights knows what can be done. You must take a bulb you know to be good and try each bulb in turn until the whole string lights up. If two bulbs are dead, give up and go buy another string. Two bulbs create a lot of combinations.

The circuit is a series circuit.

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Michael Scott is driving through the parking lot and accidentally hits Meredith as she’s walking to her car. If his car makes co

fiasKO [112]

Yes she's dead or in the hospital

6 0

3 years ago

If the temperature of an iron sphere is increased A)its density will decrease .B)its volume will decrease. C)its mass will decre

babymother [125]

Answer:

A) Its density will decrease

Explanation:

When an object is heated, its volume increases. This is due to the fact that the particles in the medium vibrate more (if it is a solid) or they move more (if it is a liquid or a gas), therefore they tend to occupy a larger space.

At the same time, the mass of the object does not change, because the mass just represents the amount of matter contained in the object, so it does not increase/decrease at different temperatures.

The density of an object is defined as the ratio between the mass (m) and the volume (V):

$d=\frac{m}{V}$

We said that the mass remains unchanged while the volume increases: since the density is inversely proportional to the volume, this means that the density decreases.

5 0

3 years ago

Read 2 more answers

what is the net force on an object that is experiencing a force of 25 N north, a force of 25 N south, a force of 50 N to the eas

REY [17]

Answer:

5 n

Explanation:

25 and 25 cancel each other out and 50-45 is 5

4 0

3 years ago

An electron and a 0.033 0-kg bullet each have a velocity of magnitude 495 m/s, accurate to within 0.010 0%. Within what lower li

lara31 [8.8K]

Answer:

1.170*10^-3 m

3.23*10^-32 m

Explanation:

To solve this, we apply Heisenberg's uncertainty principle.

the principle states that, "if we know everything about where a particle is located, then we know nothing about its momentum, and vice versa." it also can be interpreted as "if the uncertainty of the position is small, then the uncertainty of the momentum is large, and vice versa"

Δp * Δx = h/4π

m(e).Δv * Δx = h/4π

If we make Δx the subject of formula, by rearranging, we have

Δx = h / 4π * m(e).Δv

on substituting the values, we have

for the electron

Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 4.95*10^-2

Δx = 6.63*10^-34 / 5.67*10^-31

Δx = 1.170*10^-3 m

for the bullet

Δx = (6.63*10^-34) / 4 * 3.142 * 0.033*10^-31 * 4.95*10^-2

Δx = 6.63*10^-34 / 0.021

Δx = 3.23*10^-32 m

therefore, we can say that the lower limits are 1.170*10^-3 m for the electron and 3.23*10^-32 for the bullet

7 0

3 years ago

Which phase of matter contains particles that split into ions and electrons?

Lemur [1.5K]

Answer:

Plasma

Explanation:

7 0

3 years ago