The local high school is hosting the last soccer game. They charged adults, x, $5 to enter, and $3 for students, y. It cost the
2 answers:
You might be interested in
Answer:
At 90% confidence interval, the estimate of the mean breaking weight is (770.45, 778.15)
Step-by-step explanation:
Given that:
sample size n =43
sample mean x = 774.3
standard deviation = 15.4
confidence interval = 90%
At C.I of 90% , the level of significance ∝ = 1 - C.I
the level of significance ∝ = 1 - 0.90
the level of significance ∝ = 0.10
The critical value for z at this level of significance is
= 1.64
The margin of error can be computed as follows:
Margin of error =
Margin of error =
Margin of error =
Margin of error =
Margin of error = 3.8515
The mean breaking weight for the 90% confidence interval is =
=
= ( 774.3 - 3.8515 < μ < 774.3 + 3.8515 )
= (770.4485, 778.1515)
(770.45, 778.15)