Answer:
bcfh
Explanation:
HClO₄ reacts with water thus:
HClO₄ + H₂O → H₃O⁺ + ClO₄⁻
That means HClO₄ produce H₃O⁺ that decreases pH. That means the higher concentration of HClO₄ decreases pH. Thus, lower pH will be:
b) 0.2 M HClO4
The reaction of NaClO₄ is:
NaClO₄ + H₂O → OH⁻ + HClO₄ + Na⁺
The higher concentration of NaClO₄ the higher production of OH⁻ that increase pH, that means the lower concentration of NaClO₄ the lower pH, thus, the answer is:
<em>c) 0.1 M NaClO or</em>
HF reacts with water thus;
HF ⇄ H⁺ + F⁻
The equilibrium constant is:
k = [H⁺] [F⁻] / [HF] = 3,5x10⁻⁴
For HNO₂ equilibrium is:
HNO₂ ⇄ H⁺ + NO₂⁻
k = [H⁺] [NO₂⁻] / [HNO₂] = 4,5x10⁻⁴
As k value is higher for HNO₂, the concentration of H⁺ will be higher in this system doing the HNO₂ with the lower pH.
f) 0.1 M HNO2
NaOH is a strong base that produce OH⁻ that increase pH, pure water is neutral, thus, the lowe pH is:
h) pure water
I hope it helps!
