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Kisachek [45]
2 years ago
10

Bromine has an atomic mass of 79.9 amu, but only has 2 naturally occurring isotopes, Bromine-79 and Bromine-81. If Bromine-80 do

es not exist, what does that suggest about the relative abundances of Bromine-79 and Bromine-81? PLEASE HELP ME! 25 POINTSSSSS
Chemistry
1 answer:
galina1969 [7]2 years ago
5 0

Educated Guess Here!

Since Br-80 does not exist, maybe that means Br-79 or Br-81 have very unequal abundances. For example, Br-79 may have 75% abundance whereas Br-81 may have 25% abundance.

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Which of the following is not present in skeletal structures?
cupoosta [38]

Answer:

cartilage or soft tissue? you didn't give options :/

Explanation:

6 0
3 years ago
Aspirin (C9H8O4) may be synthesized by mixing salicylic acid (C7H6O3) with excess acetic anhydride (C4H6O3).
diamong [38]

Answer:

65.18% is the percent yield for this reaction.

Explanation:

C_7H_6O_3 + C_4H_6O_3\rightarrow C_9H_8O_4 + C_2H_4O_2

Moles of salicyclic acid = \frac{2.0 g}{138 g/mol}=0.01449 mol

According to reaction 1 mole of salicyclic acid gives 1 mole of aspirin .

Then 0.01449 mole of salicylic acid will give :

\frac{1}{1}\times 0.01449 mol=0.01449 mol of asprin

Mass of 0.01449 moles of aspirin :

= 0.01449 mol × 180 g/mol = 2.6082 g

Theoretical yield of aspirin = 2.6082 g

Experimental yield of aspirin = 1.7 g

The percent yield for this reaction:

\%(Yield)=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{1.7 g}{2.6082 g}\times 100=65.18\%

65.18% is the percent yield for this reaction.

5 0
3 years ago
Write the empirical formula for 3.57 g of N and 4.08 g of O. Express answer as a chemical formula.
Ad libitum [116K]
Its 4.08 i hope hopefully its helpful
7 0
3 years ago
PLEASE HELP ME ANSWER THESE QUESTIONS!
madam [21]

Answer:

1. 0.35 moles NaOH

2. 5.10x10^{-4} moles H_2SO_4

3. 505.4 g Pb

4. 1.46 g HCl (if that is wrong it's 1.5 g HCl due to sig figs)

5. 3.01x10^{23} atoms of Ag

6. 2x10^{-10} atoms of Cu

Explanation:

1. The mass of NaOH is 40g. 22.99(Na)+16(O)+1.01(H)=40 g

14 g NaOH *\frac{1 mol NaOH}{40 g NaOH} = 0.35 moles of NaOH

2. Mass of H_{2} SO_{4} = 2(1.01)+32.06+4(16) = 98.08

0.05 g H_2SO_4 ×\frac{1 mol H_2SO_4}{98.08g H_2SO_4} = 5.10 x10^{-4}

3. mass of Pb = 106.4 g

4.75 moles Pb×\frac{106.4 g Pb}{1 mol Pb} =505.4 g Pb

4. mass of HCl = 1.01 +35.45 = 36.36 g

0.04 mol HCl x \frac{36.46 g HCl}{1 mol HCl} = 1.456 = 1.5

5. 5.00 mol Ag x\frac{6.022x10^{23} atoms }{1mol Ag} = 3.01x10^{24} atoms

6. 3x10^{-10} moles Cu x\frac{6.022x10^{23} atoms}{1 mol Cu} = 1.8668x10^{14}= 2x10^{14} atoms of Cu

8 0
2 years ago
Which term refers to a substance that changes color when there is a certain concentration of hydrogen ions in a solution? (1 poi
ki77a [65]
Indicator is the answer
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2 years ago
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