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2 years ago

Which description applies to a physical property? Choose the correct answer

Chemistry

1 answer:

choli [55]2 years ago

6 0

Answer:

the third one, measured or observed without changing the identity and composition of matter. because physical property does not under go any change but can be put back.

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freezing a sealed full bottl of water leads to a broken bottle and freezing a sealed full flexible wall container of n butyl alc

Nataly [62]

Answer:

See explanation

Explanation:

We know that water begins to expand at 4°C. This is generally referred to as the anomalous behavior of water.

The implication of this is that ice has a greater volume than water. Thus ice is less dense than liquid water.

n-butyl alcohol has much less density than water. This accounts for the fact that water upon freezing breaks the bottle while n butyl alcholol leads to a container with concave walls.

Hence the density of ice is much higher than the density of n butyl alcohol.

4 0

2 years ago

Given the elements chlorine, iodine, oxygen, bromine, and fluorine, organize by increasing atomic size (atomic radius). Justify

astra-53 [7]

Answer:

hahahahah

Explanation:

3 0

2 years ago

can someone help me more clearly understand the difference between heterogeneous and homogeneous? Give an example of each plz.

const2013 [10]

Heterogenous mixtures are unevenly mixed. Like oil and vinegar in vinaigrette if it is not emulsified well enough and they separate. Any case where two things are not evenly distributed within each other.

Homogenous mixtures are evenly mixed throughout. Like salt water or kool-aid (when it's mixed).

Hope this helps!

3 0

3 years ago

15. What volume of CCI, (d = 1.6 g/cc) contain

anastassius [24]

Answer:

$\boxed{\text{(3) 9.6 L}}$

Explanation:

1. Moles of CCl₄

$n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}$

2. Molar mass of CCl₄

MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol

3. Mass of CCl₄

$m =\text{100.0 mol} \times \dfrac{\text{154.0 g}}{\text{1 mol}} = \text{15 400 g}$

4. Volume of CCl₄

$V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}$

4 0

2 years ago

How many atoms are in 175.8 grams of Hg?

dybincka [34]

5.22*22^3 should be the answer

5 0

3 years ago