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igomit [66]
3 years ago
13

Classify the polynomial according to its degree and number of terms 3x^2+8x​

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

Classifying Polynomials

Polynomials can be classified two different ways - by the number of terms and by their degree.

1. Number of terms.

A monomial has just one term. For example, 4x2 .Remember that a term contains both the variable(s) and its coefficient (the number in front of it.) So the is just one term.

A binomial has two terms. For example: 5x2 -4x

A trinomial has three terms. For example: 3y2+5y-2

Any polynomial with four or more terms is just called a polynomial. For example: 2y5+ 7y3- 5y2+9y-2

Practice classifying these polynomials by the number of terms:

1. 5y

2. 3x2-3x+1

3. 5y-10

4. 8xy

5. 3x4+x2-5x+9

Answers: 1) Monomial 2) Trinomial 3) Binomial 4) Monomial 5) Polynomial

2. Degree. The degree of the polynomial is found by looking at the term with the highest exponent on its variable(s).

Examples:

5x2-2x+1 The highest exponent is the 2 so this is a 2nd degree trinomial.

3x4+4x2The highest exponent is the 4 so this is a 4th degree binomial.

8x-1 While it appears there is no exponent, the x has an understood exponent of 1; therefore, this is a 1st degree binomial.

5 There is no variable at all. Therefore, this is a 0 degree monomial. It is 0 degree because x0=1. So technically, 5 could be written as 5x0.

3x2y5 Since both variables are part of the same term, we must add their exponents together to determine the degree. 2+5=7 so this is a 7th degree monomial.

Classify these polynomials by their degree.

1.7x3+52+1

2.6y5+9y2-3y+8

3.8x-4

4.9x2y+3

5.12x2

Answers 1) 3rd degree 2) 5th degree 3) 1st degree 4) 3rd degree 5) 2nd degree

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Comparing to the given expression, we see that x = 71°.

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3 years ago
Hypothesis Testing for Means with Small Samples
Scorpion4ik [409]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: volume of root beer in a Windsor Bottling Company can.

A sample of n=24 cans was taken and their contents measured, resulting:

X[bar]= 11.4 oz

S= 0.62 oz

Assuming that the variable has a normal distribution X~N(μ;σ²), the parameter of interest is the average contents of the root beer cans of the Windsor Bottling Company (μ)

The claim is that the population mean content of the cans is different from 12 oz, symbolically: μ ≠ 12

The statistical hypothesis (Null and alternative) have to be complementary, exhaustive and mutually exclusive. The null hypothesis is the "no change" hypothesis and always carries the "=" sign.

If the claim is μ ≠ 12, its complement is μ = 12, the expression carrying the "=" sign will be the null hypothesis and its complement will be the alternative hypothesis:

H₀: μ = 12

H₁: μ ≠ 12

α: 0.05

To test the population mean of this normal population, you have to apply a one sample t-test, with statistic:

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}

t_{H_0}= \frac{11.4-12}{\frac{0.62}{\sqrt{24} } } = -4.74

This test is two-tailed, using the critical value approach, you have to determine two rejection regions. Meaning, you'll reject the null hypothesis to small values of the statistic or to high values of the statistic.

t_{n-1;\alpha /2}= t_{23;0.025}= -2.069

t_{n-1;1-\alpha /2}= t_{23;0.975}= 2.069

The decision rule is:

If t_{H_0} ≤ -2.069 or if t_{H_0} ≥ 2.069, then you reject the null hypothesis.

If -2.069 < t_{H_0} < 2.069, then you do not reject the null hypothesis.

The value is less than the left critical value, the decision is to reject the null hypothesis.

Then you can say that with a 5% significance level, there is significant evidence to reject the null hypothesis, then the average amount of root beer of the Windsor Bottling Company is different from 12 oz, this means that the claim about the amount of root beer in the cans is correct.

I hope it helps!

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4 years ago
Round 6.85565 to the nearest tenth !
emmasim [6.3K]

Answer:

It is 6.9

Step-by-step explanation:

6.85565

put

6.85

5 can be rounded up so

6.9 is answer

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3 years ago
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