I like to reduce everything by half if I don't already know the answer.
It just so happens that is the reduced fraction.
All I did was halve 18, which is 9, and halve 34, which is 17.
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
7/10 as hundredths decimal: .07
7/10 as fraction: 7/100
It goes zero positive negative. that is from left to right
Answer:
-6
Step-by-step explanation:
Please mark as Brainliest! :)
