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serious [3.7K]
3 years ago
11

Considera los objetos A y B con una masa de 400g cada uno y ambos a una temperatura de 25°C. Si el calor específico de A es mayo

r que el de B, en las mismas condiciones de calentamiento, ¿Cuál objeto requiere más tiempo para alcanzar una temperatura de 26°C?
Physics
1 answer:
jonny [76]3 years ago
3 0

Answer:

El objeto A tardará más tiempo para aumentar la temperatura.

Explanation:

Al estar ambos objetos bajo las mismas condiciones de calentamiento, entonces, ambos objetos reciben la misma cantidad de calor por unidad de tiempo.

Si ambas tienen la misma masa y temperatura inicial, pero el objeto A tiene un mayor calor específico, entonces este objeto tardará más tiempo para incrementar su temperatura en 1 °C.

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Consider two balls on a horizontal, frictionless surface. Ball A (with mass ma) is moving toward ball B (with mass mb = 1 kg). B
Sonbull [250]

Answer:

Explanation:

When two ball of identical mass collides perfectly elastically , there is exchange of velocity between the two balls .

Here ball be was at rest initially . After collision ball A comes to rest , so there is complete exchange of velocity . Hence ball A must have same mass as that of B . mass of ball A = 1 kg .

b ) Due to complete exchange of velocity , velocity of ball A will be picked up by ball B . Hence velocity of ball B = 3.1416 m /s . Yes it will be moving in the direction of ball A .

c )

In case of perfectly inelastic collision they will become  single mass

total mass = 2 kg

applying conservation of momentum law

their common velocity after collision = 1 x 3.1416 / 2 = 1.57 m /s

d )

Applying conservation of momentum law

initial momentum = Ma x va

they move in opposite direction after collision

their total momentum after collision

1 x va - Ma va

applying law of conservation of momentum

1 x va - Ma va  = Ma va

va = 2Ma va

Ma = .5 kg .

4 0
3 years ago
A car travels 2,000 mi at a<br> constant speed of 70 mi/hr.<br> How long did the trip take?
ella [17]

Answer:

<h2>28.57 hours</h2>

Explanation:

The time taken can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance

v is the velocity

From the question we have

t =  \frac{2000}{70}  =  \frac{200}{7}  \\  = 28.571428 ...

We have the final answer as

<h3>28.57 hours</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
Please help
inysia [295]

Explanation:

Start with what you know and list your knowns and unknowns

F = ma

F= 3N

m = 6kg

a =?

3N = 6kg x a

solve for a

3N / 6kg = a

3 0
3 years ago
A wildlife researcher is tracking a flock of geese. the geese fly 3.5 km due west, then turn toward the north by 40 ∘ and fly an
kaheart [24]

To solve this problem, we can use the cosine formula for calculating the length of the displacement:

c^2 = a^2 + b^2 – 2 a b cos θ

 

where c is the displacement, a = 3.5 km, b = 4.5 km, and θ is the angle inside the triangle

 

Since the geeze turned 40° from west to north, so the angle inside the triangle must be:

θ = 180 – 40 = 140°

 

c^2 = 3.5^2 + 4.5^2 – 2 (3.5) (4.5) cos 140

c^2 = 56.63

c = 7.53 km

 

<span>So the magnitude of the displacement is 7.53 km</span>

4 0
3 years ago
Read 2 more answers
Tick (3) the correct statement about electrostatic charges.
Radda [10]

Answer:

similar type of electric charges attract one another

I think this is a coorect staement

6 0
3 years ago
Read 2 more answers
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